{ "data": { "question": { "questionId": "3214", "questionFrontendId": "2943", "categoryTitle": "Algorithms", "boundTopicId": 2539398, "title": "Maximize Area of Square Hole in Grid", "titleSlug": "maximize-area-of-square-hole-in-grid", "content": "

You are given the two integers, n and m and two integer arrays, hBars and vBars. The grid has n + 2 horizontal and m + 2 vertical bars, creating 1 x 1 unit cells. The bars are indexed starting from 1.

\n\n

You can remove some of the bars in hBars from horizontal bars and some of the bars in vBars from vertical bars. Note that other bars are fixed and cannot be removed.

\n\n

Return an integer denoting the maximum area of a square-shaped hole in the grid, after removing some bars (possibly none).

\n\n

 

\n

Example 1:

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\"\"

\n\n
\n

Input: n = 2, m = 1, hBars = [2,3], vBars = [2]

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Output: 4

\n\n

Explanation:

\n\n

The left image shows the initial grid formed by the bars. The horizontal bars are [1,2,3,4], and the vertical bars are [1,2,3].

\n\n

One way to get the maximum square-shaped hole is by removing horizontal bar 2 and vertical bar 2.

\n
\n\n

Example 2:

\n\n

\"\"

\n\n
\n

Input: n = 1, m = 1, hBars = [2], vBars = [2]

\n\n

Output: 4

\n\n

Explanation:

\n\n

To get the maximum square-shaped hole, we remove horizontal bar 2 and vertical bar 2.

\n
\n\n

Example 3:

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\"\"

\n\n
\n

Input: n = 2, m = 3, hBars = [2,3], vBars = [2,4]

\n\n

Output: 4

\n\n

Explanation:

\n\n

One way to get the maximum square-shaped hole is by removing horizontal bar 3, and vertical bar 4.

\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "最大化网格图中正方形空洞的面积", "translatedContent": "

给你一个网格图，由 n + 2 条 横线段 和 m + 2 条 竖线段 组成，一开始所有区域均为 1 x 1 的单元格。

\n\n

所有线段的编号从 1 开始。

\n\n

给你两个整数 n 和 m 。

\n\n

同时给你两个整数数组 hBars 和 vBars 。

\n\n\n\n

如果满足以下条件之一，你可以 移除 两个数组中的部分线段：

\n\n\n\n

请你返回移除一些线段后（可能不移除任何线段），剩余网格图中 最大正方形 空洞的面积，正方形空洞的意思是正方形 内部 不含有任何线段。

\n\n

 

\n\n

示例 1：

\n\n

\"\"

\n\n
\n输入：n = 2, m = 1, hBars = [2,3], vBars = [2]\n输出：4\n解释：左边的图是一开始的网格图。\n横线编号的范围是区间 [1,4] ，竖线编号的范围是区间 [1,3] 。\n可以移除的横线段为 [2,3] ，竖线段为 [2] 。\n一种得到最大正方形面积的方法是移除横线段 2 和竖线段 2 。\n操作后得到的网格图如右图所示。\n正方形空洞面积为 4。\n无法得到面积大于 4 的正方形空洞。\n所以答案为 4 。\n
\n\n

示例 2：

\n\n

\"\"

\n\n
\n输入：n = 1, m = 1, hBars = [2], vBars = [2]\n输出：4\n解释：左边的图是一开始的网格图。\n横线编号的范围是区间 [1,3] ，竖线编号的范围是区间 [1,3] 。\n可以移除的横线段为 [2] ，竖线段为 [2] 。\n一种得到最大正方形面积的方法是移除横线段 2 和竖线段 2 。\n操作后得到的网格图如右图所示。\n正方形空洞面积为 4。\n无法得到面积大于 4 的正方形空洞。\n所以答案为 4 。\n
\n\n

示例 3：

\n\n

\"\"

\n\n
\n输入：n = 2, m = 3, hBars = [2,3], vBars = [2,3,4]\n输出：9\n解释：左边的图是一开始的网格图。\n横线编号的范围是区间 [1,4] ，竖线编号的范围是区间 [1,5] 。\n可以移除的横线段为 [2,3] ，竖线段为 [2,3,4] 。\n一种得到最大正方形面积的方法是移除横线段 2、3 和竖线段 3、4 。\n操作后得到的网格图如右图所示。\n正方形空洞面积为 9。\n无法得到面积大于 9 的正方形空洞。\n所以答案为 9 。\n
\n\n

 

\n\n

提示：

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m, hBars, vBars):\n \"\"\"\n :type n: int\n :type m: int\n :type hBars: List[int]\n :type vBars: List[int]\n :rtype: int\n \"\"\"\n ", "__typename": "CodeSnippetNode" }, { "lang": "Python3", "langSlug": "python3", "code": "class Solution:\n def maximizeSquareHoleArea(self, n: int, m: int, hBars: List[int], vBars: List[int]) -> int:\n ", "__typename": "CodeSnippetNode" }, { "lang": "C", "langSlug": "c", "code": "int maximizeSquareHoleArea(int n, int m, int* hBars, int hBarsSize, int* vBars, int vBarsSize) {\n \n}", "__typename": "CodeSnippetNode" }, { "lang": "C#", "langSlug": "csharp", "code": "public class Solution {\n public int MaximizeSquareHoleArea(int n, int m, int[] hBars, int[] vBars) {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "JavaScript", "langSlug": "javascript", "code": "/**\n * @param {number} n\n * @param {number} m\n * @param {number[]} hBars\n * @param {number[]} vBars\n * @return {number}\n */\nvar maximizeSquareHoleArea = function(n, m, hBars, vBars) 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