You are given an array of integers stones where stones[i] is the weight of the ith stone.
We are playing a game with the stones. On each turn, we choose the heaviest two stones and smash them together. Suppose the heaviest two stones have weights x and y with x <= y. The result of this smash is:
x == y, both stones are destroyed, andx != y, the stone of weight x is destroyed, and the stone of weight y has new weight y - x.At the end of the game, there is at most one stone left.
\n\nReturn the weight of the last remaining stone. If there are no stones left, return 0.
\n
Example 1:
\n\n\nInput: stones = [2,7,4,1,8,1]\nOutput: 1\nExplanation: \nWe combine 7 and 8 to get 1 so the array converts to [2,4,1,1,1] then,\nwe combine 2 and 4 to get 2 so the array converts to [2,1,1,1] then,\nwe combine 2 and 1 to get 1 so the array converts to [1,1,1] then,\nwe combine 1 and 1 to get 0 so the array converts to [1] then that's the value of the last stone.\n\n\n
Example 2:
\n\n\nInput: stones = [1]\nOutput: 1\n\n\n
\n
Constraints:
\n\n1 <= stones.length <= 301 <= stones[i] <= 1000有一堆石头，每块石头的重量都是正整数。
\n\n每一回合，从中选出两块 最重的 石头，然后将它们一起粉碎。假设石头的重量分别为 x 和 y，且 x <= y。那么粉碎的可能结果如下：
x == y，那么两块石头都会被完全粉碎；x != y，那么重量为 x 的石头将会完全粉碎，而重量为 y 的石头新重量为 y-x。最后，最多只会剩下一块石头。返回此石头的重量。如果没有石头剩下，就返回 0。
\n\n
示例：
\n\n\n输入：[2,7,4,1,8,1]\n输出：1\n解释：\n先选出 7 和 8，得到 1，所以数组转换为 [2,4,1,1,1]，\n再选出 2 和 4，得到 2，所以数组转换为 [2,1,1,1]，\n接着是 2 和 1，得到 1，所以数组转换为 [1,1,1]，\n最后选出 1 和 1，得到 0，最终数组转换为 [1]，这就是最后剩下那块石头的重量。\n\n
\n\n
提示：
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