You are given a string s consisting of characters 'U', 'D', 'L', and 'R', representing moves on an infinite 2D Cartesian grid.
'U': Move from (x, y) to (x, y + 1).'D': Move from (x, y) to (x, y - 1).'L': Move from (x, y) to (x - 1, y).'R': Move from (x, y) to (x + 1, y).You are also given a positive integer k.
You must choose and remove exactly one contiguous substring of length k from s. Then, start from coordinate (0, 0) and perform the remaining moves in order.
Return an integer denoting the number of distinct final coordinates reachable.
\n\n\n
Example 1:
\n\nInput: s = "LUL", k = 1
\n\nOutput: 2
\n\nExplanation:
\n\nAfter removing a substring of length 1, s can be "UL", "LL" or "LU". Following these moves, the final coordinates will be (-1, 1), (-2, 0) and (-1, 1) respectively. There are two distinct points (-1, 1) and (-2, 0) so the answer is 2.
Example 2:
\n\nInput: s = "UDLR", k = 4
\n\nOutput: 1
\n\nExplanation:
\n\nAfter removing a substring of length 4, s can only be the empty string. The final coordinates will be (0, 0). There is only one distinct point (0, 0) so the answer is 1.
Example 3:
\n\nInput: s = "UU", k = 1
\n\nOutput: 1
\n\nExplanation:
\n\nAfter removing a substring of length 1, s becomes "U", which always ends at (0, 1), so there is only one distinct final coordinate.
\n
Constraints:
\n\n1 <= s.length <= 105s consists of only 'U', 'D', 'L', and 'R'.1 <= k <= s.length给你一个由字符 'U'、'D'、'L' 和 'R' 组成的字符串 s，表示在无限的二维笛卡尔网格上的移动。
'U': 从 (x, y) 移动到 (x, y + 1)。'D': 从 (x, y) 移动到 (x, y - 1)。'L': 从 (x, y) 移动到 (x - 1, y)。'R': 从 (x, y) 移动到 (x + 1, y)。你还得到了一个正整数 k。
你 必须 选择并移除 恰好一个 长度为 k 的连续子字符串 s。然后，从坐标 (0, 0) 开始，按顺序执行剩余的移动。
返回可到达的 不同 最终坐标的数量。
\n\n\n\n
示例 1:
\n\n输入：s = \"LUL\", k = 1
\n\n输出：2
\n\n解释：
\n\n移除长度为 1 的子字符串后，s 可以是 \"UL\"、\"LL\" 或 \"LU\"。执行这些移动后，最终坐标将分别是 (-1, 1)、(-2, 0) 和 (-1, 1)。有两个不同的点 (-1, 1) 和 (-2, 0)，因此答案是 2。
示例 2:
\n\n输入：s = \"UDLR\", k = 4
\n\n输出：1
\n\n解释：
\n\n移除长度为 4 的子字符串后，s 只能是空字符串。最终坐标将是 (0, 0)。只有一个不同的点 (0, 0)，因此答案是 1。
示例 3:
\n\n输入：s = \"UU\", k = 1
\n\n输出：1
\n\n解释：
\n\n移除长度为 1 的子字符串后，s 变为 \"U\"，它总是以 (0, 1) 结束，因此只有一个不同的最终坐标。
\n\n
提示:
\n\n1 <= s.length <= 105s 只包含 'U'、'D'、'L' 和 'R'。1 <= k <= s.lengthx-coordinate and y-coordinate.",
"Using the prefix sum arrays, compute the x-coordinate and y-coordinate after removing a subarray of size k."
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