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https://gitee.com/coder-xiaomo/leetcode-problemset
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update
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@@ -11,7 +11,7 @@
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"translatedContent": null,
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"isPaidOnly": false,
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"difficulty": "Medium",
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"likes": 1259,
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"likes": 1263,
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"dislikes": 52,
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"isLiked": null,
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"similarQuestions": "[{\"title\": \"Sliding Window Maximum\", \"titleSlug\": \"sliding-window-maximum\", \"difficulty\": \"Hard\", \"translatedTitle\": null}, {\"title\": \"Jump Game VII\", \"titleSlug\": \"jump-game-vii\", \"difficulty\": \"Medium\", \"translatedTitle\": null}]",
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@@ -167,7 +167,7 @@
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"__typename": "CodeSnippetNode"
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}
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],
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"stats": "{\"totalAccepted\": \"41.5K\", \"totalSubmission\": \"97.4K\", \"totalAcceptedRaw\": 41530, \"totalSubmissionRaw\": 97448, \"acRate\": \"42.6%\"}",
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"stats": "{\"totalAccepted\": \"41.6K\", \"totalSubmission\": \"97.6K\", \"totalAcceptedRaw\": 41608, \"totalSubmissionRaw\": 97604, \"acRate\": \"42.6%\"}",
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"hints": [
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"Let dp[i] be \"the maximum score to reach the end starting at index i\". The answer for dp[i] is nums[i] + max{dp[i+j]} for 1 <= j <= k. That gives an O(n*k) solution.",
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"Instead of checking every j for every i, keep track of the largest dp[i] values in a heap and calculate dp[i] from right to left. When the largest value in the heap is out of bounds of the current index, remove it and keep checking."
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