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leetcode/problem/painting-the-walls.html
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leetcode/problem/painting-the-walls.html
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<p>You are given two <strong>0-indexed</strong> integer arrays, <code>cost</code> and <code>time</code>, of size <code>n</code> representing the costs and the time taken to paint <code>n</code> different walls respectively. There are two painters available:</p>
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<ul>
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<li>A<strong> paid painter</strong> that paints the <code>i<sup>th</sup></code> wall in <code>time[i]</code> units of time and takes <code>cost[i]</code> units of money.</li>
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<li>A<strong> free painter</strong> that paints <strong>any</strong> wall in <code>1</code> unit of time at a cost of <code>0</code>. But the free painter can only be used if the paid painter is already <strong>occupied</strong>.</li>
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</ul>
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<p>Return <em>the minimum amount of money required to paint the </em><code>n</code><em> walls.</em></p>
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<p> </p>
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<p><strong class="example">Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> cost = [1,2,3,2], time = [1,2,3,2]
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<strong>Output:</strong> 3
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<strong>Explanation:</strong> The walls at index 0 and 1 will be painted by the paid painter, and it will take 3 units of time; meanwhile, the free painter will paint the walls at index 2 and 3, free of cost in 2 units of time. Thus, the total cost is 1 + 2 = 3.
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</pre>
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<p><strong class="example">Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> cost = [2,3,4,2], time = [1,1,1,1]
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<strong>Output:</strong> 4
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<strong>Explanation:</strong> The walls at index 0 and 3 will be painted by the paid painter, and it will take 2 units of time; meanwhile, the free painter will paint the walls at index 1 and 2, free of cost in 2 units of time. Thus, the total cost is 2 + 2 = 4.
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</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>1 <= cost.length <= 500</code></li>
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<li><code>cost.length == time.length</code></li>
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<li><code>1 <= cost[i] <= 10<sup>6</sup></code></li>
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<li><code>1 <= time[i] <= 500</code></li>
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</ul>
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