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<p>Your laptop keyboard is faulty, and whenever you type a character <code>'i'</code> on it, it reverses the string that you have written. Typing other characters works as expected.</p>
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<p>You are given a <strong>0-indexed</strong> string <code>s</code>, and you type each character of <code>s</code> using your faulty keyboard.</p>
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<p>Return <em>the final string that will be present on your laptop screen.</em></p>
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<p> </p>
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<p><strong class="example">Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> s = "string"
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<strong>Output:</strong> "rtsng"
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<strong>Explanation:</strong>
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After typing first character, the text on the screen is "s".
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After the second character, the text is "st".
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After the third character, the text is "str".
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Since the fourth character is an 'i', the text gets reversed and becomes "rts".
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After the fifth character, the text is "rtsn".
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After the sixth character, the text is "rtsng".
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Therefore, we return "rtsng".
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</pre>
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<p><strong class="example">Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> s = "poiinter"
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<strong>Output:</strong> "ponter"
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<strong>Explanation:</strong>
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After the first character, the text on the screen is "p".
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After the second character, the text is "po".
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Since the third character you type is an 'i', the text gets reversed and becomes "op".
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Since the fourth character you type is an 'i', the text gets reversed and becomes "po".
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After the fifth character, the text is "pon".
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After the sixth character, the text is "pont".
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After the seventh character, the text is "ponte".
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After the eighth character, the text is "ponter".
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Therefore, we return "ponter".</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>1 <= s.length <= 100</code></li>
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<li><code>s</code> consists of lowercase English letters.</li>
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<li><code>s[0] != 'i'</code></li>
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</ul>
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