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add leetcode problem-cn part3

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<p>给定一副牌,每张牌上都写着一个整数。</p>
<p>此时,你需要选定一个数字 <code>X</code>,使我们可以将整副牌按下述规则分成 1 组或更多组:</p>
<ul>
<li>每组都有&nbsp;<code>X</code>&nbsp;张牌。</li>
<li>组内所有的牌上都写着相同的整数。</li>
</ul>
<p>仅当你可选的 <code>X &gt;= 2</code> 时返回&nbsp;<code>true</code></p>
<p>&nbsp;</p>
<p><strong>示例 1</strong></p>
<pre>
<strong>输入:</strong>deck = [1,2,3,4,4,3,2,1]
<strong>输出:</strong>true
<strong>解释:</strong>可行的分组是 [1,1][2,2][3,3][4,4]
</pre>
<p><strong>示例 2</strong></p>
<pre>
<strong>输入:</strong>deck = [1,1,1,2,2,2,3,3]
<strong>输出:</strong>false
<strong>解释:</strong>没有满足要求的分组。
</pre>
<p><br />
<strong>提示:</strong></p>
<ul>
<li><code>1 &lt;= deck.length &lt;= 10<sup>4</sup></code></li>
<li><code>0 &lt;= deck[i] &lt; 10<sup>4</sup></code></li>
</ul>