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leetcode-cn/problem (Chinese)/查找超预订员工 [find-overbooked-employees].html Normal file
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<p>表：<code>employees</code></p>
<pre>
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| employee_id | int |
| employee_name | varchar |
| department | varchar |
+---------------+---------+
employee_id 是这张表的唯一主键。
每一行包含一个员工和他们部门的信息。
</pre>
<p>表：<code>meetings</code></p>
<pre>
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| meeting_id | int |
| employee_id | int |
| meeting_date | date |
| meeting_type | varchar |
| duration_hours| decimal |
+---------------+---------+
meeting_id 是这张表的唯一主键。
每一行表示一位员工参加的会议。meeting_type 可以是 'Team'，'Client' 或 'Training'。
</pre>
<p>编写一个解决方案来查找会议密集型的员工&nbsp;-&nbsp; 在任何给定周内，花费超过 <code>50%</code> 工作时间在会议上的员工。</p>
<ul>
<li>假定一个标准工作周是&nbsp;<code>40</code><strong> 小时</strong></li>
<li>计算每位员工 <strong>每周</strong>（<strong>周一至周日</strong>）的 <strong>总会议小时数</strong></li>
<li>员工如果每周会议时间超过 <code>20</code> 小时（<code>40</code> 小时工作时间的 <code>50%</code>），则被视为会议密集型。</li>
<li>统计每位员工有多少周是会议密集周</li>
<li><strong>仅查找 至少</strong> <code>2</code> 周会议密集的员工</li>
</ul>
<p>返回结果表按会议密集周的数量降序排列，然后按员工姓名升序排列。结果格式如下所示。</p>
<p>&nbsp;</p>
<p><strong class="example">示例：</strong></p>
<div class="example-block">
<p><strong>Input:</strong></p>
<p>employees 表：</p>
<pre class="example-io">
+-------------+----------------+-------------+
| employee_id | employee_name | department |
+-------------+----------------+-------------+
| 1 | Alice Johnson | Engineering |
| 2 | Bob Smith | Marketing |
| 3 | Carol Davis | Sales |
| 4 | David Wilson | Engineering |
| 5 | Emma Brown | HR |
+-------------+----------------+-------------+
</pre>
<p>meetings 表：</p>
<pre class="example-io">
+------------+-------------+--------------+--------------+----------------+
| meeting_id | employee_id | meeting_date | meeting_type | duration_hours |
+------------+-------------+--------------+--------------+----------------+
| 1 | 1 | 2023-06-05 | Team | 8.0 |
| 2 | 1 | 2023-06-06 | Client | 6.0 |
| 3 | 1 | 2023-06-07 | Training | 7.0 |
| 4 | 1 | 2023-06-12 | Team | 12.0 |
| 5 | 1 | 2023-06-13 | Client | 9.0 |
| 6 | 2 | 2023-06-05 | Team | 15.0 |
| 7 | 2 | 2023-06-06 | Client | 8.0 |
| 8 | 2 | 2023-06-12 | Training | 10.0 |
| 9 | 3 | 2023-06-05 | Team | 4.0 |
| 10 | 3 | 2023-06-06 | Client | 3.0 |
| 11 | 4 | 2023-06-05 | Team | 25.0 |
| 12 | 4 | 2023-06-19 | Client | 22.0 |
| 13 | 5 | 2023-06-05 | Training | 2.0 |
+------------+-------------+--------------+--------------+----------------+
</pre>
<p><strong>输出：</strong></p>
<pre class="example-io">
+-------------+----------------+-------------+---------------------+
| employee_id | employee_name | department | meeting_heavy_weeks |
+-------------+----------------+-------------+---------------------+
| 1 | Alice Johnson | Engineering | 2 |
| 4 | David Wilson | Engineering | 2 |
+-------------+----------------+-------------+---------------------+
</pre>
<p><strong>解释：</strong></p>
<ul>
<li><strong>Alice Johnson (employee_id = 1):</strong>
<ul>
<li>6 月 5 日至 11 日（2023-06-05 至 2023-06-11）：8.0 + 6.0 + 7.0 = 21.0 小时（&gt; 20 小时）</li>
<li>6 月 12&nbsp;日至 18&nbsp;日（2023-06-12 至 2023-06-18）: 12.0 + 9.0 = 21.0 小时（&gt; 20 小时）</li>
<li>2 周会议密集</li>
</ul>
</li>
<li><strong>David Wilson (employee_id = 4):</strong>
<ul>
<li>6 月 5 日至 11 日：25.0 小时（&gt; 20 小时）</li>
<li>6 月 19&nbsp;日至 25&nbsp;日：22.0 小时（&gt; 20 小时）</li>
<li>2 周会议密集</li>
</ul>
</li>
<li><strong>未包含的员工：</strong>
<ul>
<li>Bob Smith（employee_id = 2）：6 月 5 日至 11 日：15.0 + 8.0 = 23.0 小时（&gt; 20），6 月 12&nbsp;日至 18&nbsp;日：10.0 小时（&lt; 20）。只有 1 个会议密集周。</li>
<li>Carol Davis（employee_id = 3）：6 月 5 日至 11 日：4.0 + 3.0 = 7.0 小时（&lt; 20）。没有会议密集周。</li>
<li>Emma Brown（employee_id = 5）：6 月 5 日至 11 日：2.0 小时（&lt; 20）。没有会议密集周。</li>
</ul>
</li>
</ul>
<p>结果表按 meeting_heavy_weeks 降序排列，然后按员工姓名升序排列。</p>
</div>