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	add leetcode problem-cn part1
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<p>You are given an <code>m x n</code> binary matrix <code>mat</code> of <code>1</code>'s (representing soldiers) and <code>0</code>'s (representing civilians). The soldiers are positioned <strong>in front</strong> of the civilians. That is, all the <code>1</code>'s will appear to the <strong>left</strong> of all the <code>0</code>'s in each row.</p>
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<p>A row <code>i</code> is <strong>weaker</strong> than a row <code>j</code> if one of the following is true:</p>
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<ul>
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	<li>The number of soldiers in row <code>i</code> is less than the number of soldiers in row <code>j</code>.</li>
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	<li>Both rows have the same number of soldiers and <code>i < j</code>.</li>
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</ul>
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<p>Return <em>the indices of the </em><code>k</code><em> <strong>weakest</strong> rows in the matrix ordered from weakest to strongest</em>.</p>
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<p> </p>
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<p><strong>Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> mat = 
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[[1,1,0,0,0],
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 [1,1,1,1,0],
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 [1,0,0,0,0],
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 [1,1,0,0,0],
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 [1,1,1,1,1]], 
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k = 3
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<strong>Output:</strong> [2,0,3]
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<strong>Explanation:</strong> 
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The number of soldiers in each row is: 
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- Row 0: 2 
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- Row 1: 4 
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- Row 2: 1 
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- Row 3: 2 
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- Row 4: 5 
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The rows ordered from weakest to strongest are [2,0,3,1,4].
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</pre>
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<p><strong>Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> mat = 
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[[1,0,0,0],
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 [1,1,1,1],
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 [1,0,0,0],
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 [1,0,0,0]], 
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k = 2
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<strong>Output:</strong> [0,2]
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<strong>Explanation:</strong> 
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The number of soldiers in each row is: 
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- Row 0: 1 
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- Row 1: 4 
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- Row 2: 1 
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- Row 3: 1 
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The rows ordered from weakest to strongest are [0,2,3,1].
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</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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	<li><code>m == mat.length</code></li>
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	<li><code>n == mat[i].length</code></li>
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	<li><code>2 <= n, m <= 100</code></li>
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	<li><code>1 <= k <= m</code></li>
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	<li><code>matrix[i][j]</code> is either 0 or 1.</li>
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</ul>
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