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	add leetcode problem-cn part1
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<p>For two strings <code>s</code> and <code>t</code>, we say "<code>t</code> divides <code>s</code>" if and only if <code>s = t + ... + t</code> (i.e., <code>t</code> is concatenated with itself one or more times).</p>
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<p>Given two strings <code>str1</code> and <code>str2</code>, return <em>the largest string </em><code>x</code><em> such that </em><code>x</code><em> divides both </em><code>str1</code><em> and </em><code>str2</code>.</p>
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<p> </p>
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<p><strong>Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> str1 = "ABCABC", str2 = "ABC"
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<strong>Output:</strong> "ABC"
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</pre>
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<p><strong>Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> str1 = "ABABAB", str2 = "ABAB"
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<strong>Output:</strong> "AB"
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</pre>
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<p><strong>Example 3:</strong></p>
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<pre>
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<strong>Input:</strong> str1 = "LEET", str2 = "CODE"
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<strong>Output:</strong> ""
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</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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	<li><code>1 <= str1.length, str2.length <= 1000</code></li>
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	<li><code>str1</code> and <code>str2</code> consist of English uppercase letters.</li>
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</ul>
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