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add leetcode problem-cn part1
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<p>给你一个 <code>m * n</code> 的矩阵,矩阵中的元素不是 <code>0</code> 就是 <code>1</code>,请你统计并返回其中完全由 <code>1</code> 组成的 <strong>正方形</strong> 子矩阵的个数。</p>
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<p> </p>
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<p><strong>示例 1:</strong></p>
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<pre><strong>输入:</strong>matrix =
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[
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[0,1,1,1],
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[1,1,1,1],
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[0,1,1,1]
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]
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<strong>输出:</strong>15
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<strong>解释:</strong>
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边长为 1 的正方形有 <strong>10</strong> 个。
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边长为 2 的正方形有 <strong>4</strong> 个。
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边长为 3 的正方形有 <strong>1</strong> 个。
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正方形的总数 = 10 + 4 + 1 = <strong>15</strong>.
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</pre>
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<p><strong>示例 2:</strong></p>
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<pre><strong>输入:</strong>matrix =
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[
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[1,0,1],
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[1,1,0],
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[1,1,0]
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]
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<strong>输出:</strong>7
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<strong>解释:</strong>
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边长为 1 的正方形有 <strong>6</strong> 个。
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边长为 2 的正方形有 <strong>1</strong> 个。
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正方形的总数 = 6 + 1 = <strong>7</strong>.
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</pre>
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<p> </p>
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<p><strong>提示:</strong></p>
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<ul>
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<li><code>1 <= arr.length <= 300</code></li>
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<li><code>1 <= arr[0].length <= 300</code></li>
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<li><code>0 <= arr[i][j] <= 1</code></li>
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</ul>
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