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add leetcode problem-cn part1
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<p>泰波那契序列 T<sub>n</sub> 定义如下: </p>
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<p>T<sub>0</sub> = 0, T<sub>1</sub> = 1, T<sub>2</sub> = 1, 且在 n >= 0 的条件下 T<sub>n+3</sub> = T<sub>n</sub> + T<sub>n+1</sub> + T<sub>n+2</sub></p>
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<p>给你整数 <code>n</code>,请返回第 n 个泰波那契数 T<sub>n </sub>的值。</p>
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<p> </p>
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<p><strong>示例 1:</strong></p>
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<pre><strong>输入:</strong>n = 4
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<strong>输出:</strong>4
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<strong>解释:</strong>
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T_3 = 0 + 1 + 1 = 2
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T_4 = 1 + 1 + 2 = 4
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</pre>
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<p><strong>示例 2:</strong></p>
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<pre><strong>输入:</strong>n = 25
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<strong>输出:</strong>1389537
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</pre>
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<p> </p>
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<p><strong>提示:</strong></p>
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<ul>
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<li><code>0 <= n <= 37</code></li>
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<li>答案保证是一个 32 位整数,即 <code>answer <= 2^31 - 1</code>。</li>
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</ul>
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