1
0
mirror of https://gitee.com/coder-xiaomo/leetcode-problemset synced 2025-09-13 19:31:42 +08:00
Code Issues Projects Releases Wiki Activity GitHub Gitee

add leetcode problem-cn part1

This commit is contained in:
2022-03-27 20:37:52 +08:00
parent 8e542045d1
commit c554fc6908
1285 changed files with 108123 additions and 0 deletions

View File

@@ -0,0 +1,35 @@
<p>给你一个二叉树的根节点&nbsp;<code>root</code>。设根节点位于二叉树的第 <code>1</code> 层,而根节点的子节点位于第 <code>2</code> 层,依此类推。</p>
<p>请返回层内元素之和 <strong>最大</strong> 的那几层(可能只有一层)的层号,并返回其中&nbsp;<strong>最小</strong> 的那个。</p>
<p>&nbsp;</p>
<p><strong>示例 1</strong></p>
<p><strong><img alt="" src="https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2019/08/17/capture.jpeg" style="height: 175px; width: 200px;" /></strong></p>
<pre>
<strong>输入:</strong>root = [1,7,0,7,-8,null,null]
<strong>输出:</strong>2
<strong>解释:</strong>
第 1 层各元素之和为 1
第 2 层各元素之和为 7 + 0 = 7
第 3 层各元素之和为 7 + -8 = -1
所以我们返回第 2 层的层号,它的层内元素之和最大。
</pre>
<p><strong>示例 2</strong></p>
<pre>
<strong>输入:</strong>root = [989,null,10250,98693,-89388,null,null,null,-32127]
<strong>输出:</strong>2
</pre>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li>树中的节点数在<meta charset="UTF-8" />&nbsp;<code>[1, 10<sup>4</sup>]</code>范围内<meta charset="UTF-8" /></li>
<li><code>-10<sup>5</sup>&nbsp;&lt;= Node.val &lt;= 10<sup>5</sup></code></li>
</ul>