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存量题库数据更新

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小墨
2023-12-09 18:42:21 +08:00
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commit c198538f10
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leetcode-cn/problem (English)/账户合并(English) [accounts-merge].html
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@@ -5,7 +5,7 @@
<p>After merging the accounts, return the accounts in the following format: the first element of each account is the name, and the rest of the elements are emails <strong>in sorted order</strong>. The accounts themselves can be returned in <strong>any order</strong>.</p>
<p>&nbsp;</p>
<p><strong>Example 1:</strong></p>
<p><strong class="example">Example 1:</strong></p>
<pre>
<strong>Input:</strong> accounts = [[&quot;John&quot;,&quot;johnsmith@mail.com&quot;,&quot;john_newyork@mail.com&quot;],[&quot;John&quot;,&quot;johnsmith@mail.com&quot;,&quot;john00@mail.com&quot;],[&quot;Mary&quot;,&quot;mary@mail.com&quot;],[&quot;John&quot;,&quot;johnnybravo@mail.com&quot;]]
@@ -17,7 +17,7 @@ We could return these lists in any order, for example the answer [[&#39;Mary&#39
[&#39;John&#39;, &#39;john00@mail.com&#39;, &#39;john_newyork@mail.com&#39;, &#39;johnsmith@mail.com&#39;]] would still be accepted.
</pre>
<p><strong>Example 2:</strong></p>
<p><strong class="example">Example 2:</strong></p>
<pre>
<strong>Input:</strong> accounts = [[&quot;Gabe&quot;,&quot;Gabe0@m.co&quot;,&quot;Gabe3@m.co&quot;,&quot;Gabe1@m.co&quot;],[&quot;Kevin&quot;,&quot;Kevin3@m.co&quot;,&quot;Kevin5@m.co&quot;,&quot;Kevin0@m.co&quot;],[&quot;Ethan&quot;,&quot;Ethan5@m.co&quot;,&quot;Ethan4@m.co&quot;,&quot;Ethan0@m.co&quot;],[&quot;Hanzo&quot;,&quot;Hanzo3@m.co&quot;,&quot;Hanzo1@m.co&quot;,&quot;Hanzo0@m.co&quot;],[&quot;Fern&quot;,&quot;Fern5@m.co&quot;,&quot;Fern1@m.co&quot;,&quot;Fern0@m.co&quot;]]
@@ -30,7 +30,7 @@ We could return these lists in any order, for example the answer [[&#39;Mary&#39
<ul>
<li><code>1 &lt;= accounts.length &lt;= 1000</code></li>
<li><code>2 &lt;= accounts[i].length &lt;= 10</code></li>
<li><code>1 &lt;= accounts[i][j] &lt;= 30</code></li>
<li><code>1 &lt;= accounts[i][j].length &lt;= 30</code></li>
<li><code>accounts[i][0]</code> consists of English letters.</li>
<li><code>accounts[i][j] (for j &gt; 0)</code> is a valid email.</li>
</ul>