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2023-12-09 18:42:21 +08:00
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leetcode-cn/problem (English)/移除元素(English) [remove-element].html
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<p>Given an integer array <code>nums</code> and an integer <code>val</code>, remove all occurrences of <code>val</code> in <code>nums</code> <a href="https://en.wikipedia.org/wiki/In-place_algorithm" target="_blank"><strong>in-place</strong></a>. The relative order of the elements may be changed.</p>
<p>Given an integer array <code>nums</code> and an integer <code>val</code>, remove all occurrences of <code>val</code> in <code>nums</code> <a href="https://en.wikipedia.org/wiki/In-place_algorithm" target="_blank"><strong>in-place</strong></a>. The order of the elements may be changed. Then return <em>the number of elements in </em><code>nums</code><em> which are not equal to </em><code>val</code>.</p>
<p>Since it is impossible to change the length of the array in some languages, you must instead have the result be placed in the <strong>first part</strong> of the array <code>nums</code>. More formally, if there are <code>k</code> elements after removing the duplicates, then the first <code>k</code> elements of <code>nums</code> should hold the final result. It does not matter what you leave beyond the first <code>k</code> elements.</p>
<p>Consider the number of elements in <code>nums</code> which are not equal to <code>val</code> be <code>k</code>, to get accepted, you need to do the following things:</p>
<p>Return <code>k</code><em> after placing the final result in the first </em><code>k</code><em> slots of </em><code>nums</code>.</p>
<p>Do <strong>not</strong> allocate extra space for another array. You must do this by <strong>modifying the input array <a href="https://en.wikipedia.org/wiki/In-place_algorithm" target="_blank">in-place</a></strong> with O(1) extra memory.</p>
<ul>
<li>Change the array <code>nums</code> such that the first <code>k</code> elements of <code>nums</code> contain the elements which are not equal to <code>val</code>. The remaining elements of <code>nums</code> are not important as well as the size of <code>nums</code>.</li>
<li>Return <code>k</code>.</li>
</ul>
<p><strong>Custom Judge:</strong></p>
@@ -28,7 +29,7 @@ for (int i = 0; i &lt; actualLength; i++) {
<p>If all assertions pass, then your solution will be <strong>accepted</strong>.</p>
<p>&nbsp;</p>
<p><strong>Example 1:</strong></p>
<p><strong class="example">Example 1:</strong></p>
<pre>
<strong>Input:</strong> nums = [3,2,2,3], val = 3
@@ -37,7 +38,7 @@ for (int i = 0; i &lt; actualLength; i++) {
It does not matter what you leave beyond the returned k (hence they are underscores).
</pre>
<p><strong>Example 2:</strong></p>
<p><strong class="example">Example 2:</strong></p>
<pre>
<strong>Input:</strong> nums = [0,1,2,2,3,0,4,2], val = 2