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<p>Assuming both players play <strong>optimally</strong>, return <code>true</code> <em>if Alice wins and</em> <code>false</code> <em>if Bob wins</em>.</p>
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<p> </p>
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<p><strong>Example 1:</strong></p>
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<p><strong class="example">Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> stones = [2,1]
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The sum of the removed stones is 1 + 2 = 3 and is divisible by 3. Therefore, Bob loses and Alice wins the game.
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</pre>
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<p><strong>Example 2:</strong></p>
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<p><strong class="example">Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> stones = [2]
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@@ -25,7 +25,7 @@ The sum of the removed stones is 1 + 2 = 3 and is divisible by 3. Therefore, Bob
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Since all the stones are removed and the sum of values is not divisible by 3, Bob wins the game.
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</pre>
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<p><strong>Example 3:</strong></p>
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<p><strong class="example">Example 3:</strong></p>
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<pre>
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<strong>Input:</strong> stones = [5,1,2,4,3]
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