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leetcode-cn/problem (Chinese)/驼峰式匹配 [camelcase-matching].html
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<p>如果我们可以将<strong>小写字母</strong>插入模式串&nbsp;<code>pattern</code>&nbsp;得到待查询项&nbsp;<code>query</code>，那么待查询项与给定模式串匹配。（我们可以在任何位置插入每个字符，也可以插入 0 个字符。）</p>
<p>给你一个字符串数组 <code>queries</code>，和一个表示模式的字符串&nbsp;<code>pattern</code>，请你返回一个布尔数组 <code>answer</code> 。只有在待查项&nbsp;<code>queries[i]</code> 与模式串&nbsp;<code>pattern</code> 匹配时，&nbsp;<code>answer[i]</code>&nbsp;才为 <code>true</code>，否则为 <code>false</code>。</p>
<p>给定待查询列表&nbsp;<code>queries</code>，和模式串&nbsp;<code>pattern</code>，返回由布尔值组成的答案列表&nbsp;<code>answer</code>。只有在待查项&nbsp;<code>queries[i]</code> 与模式串&nbsp;<code>pattern</code> 匹配时，&nbsp;<code>answer[i]</code>&nbsp;才为 <code>true</code>，否则为 <code>false</code>。</p>
<p>如果可以将<strong>小写字母</strong>插入模式串&nbsp;<code>pattern</code>&nbsp;得到待查询项&nbsp;<code>query</code>，那么待查询项与给定模式串匹配。可以在任何位置插入每个字符，也可以不插入字符。</p>
<p>&nbsp;</p>
<p><strong>示例 1：</strong></p>
<pre><strong>输入：</strong>queries = [&quot;FooBar&quot;,&quot;FooBarTest&quot;,&quot;FootBall&quot;,&quot;FrameBuffer&quot;,&quot;ForceFeedBack&quot;], pattern = &quot;FB&quot;
<pre>
<strong>输入：</strong>queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FB"
<strong>输出：</strong>[true,false,true,true,false]
<strong>示例：</strong>
&quot;FooBar&quot; 可以这样生成：&quot;F&quot; + &quot;oo&quot; + &quot;B&quot; + &quot;ar&quot;。
&quot;FootBall&quot; 可以这样生成：&quot;F&quot; + &quot;oot&quot; + &quot;B&quot; + &quot;all&quot;.
&quot;FrameBuffer&quot; 可以这样生成：&quot;F&quot; + &quot;rame&quot; + &quot;B&quot; + &quot;uffer&quot;.</pre>
"FooBar" 可以这样生成："F" + "oo" + "B" + "ar"。
"FootBall" 可以这样生成："F" + "oot" + "B" + "all".
"FrameBuffer" 可以这样生成："F" + "rame" + "B" + "uffer".</pre>
<p><strong>示例 2：</strong></p>
<pre><strong>输入：</strong>queries = [&quot;FooBar&quot;,&quot;FooBarTest&quot;,&quot;FootBall&quot;,&quot;FrameBuffer&quot;,&quot;ForceFeedBack&quot;], pattern = &quot;FoBa&quot;
<pre>
<strong>输入：</strong>queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FoBa"
<strong>输出：</strong>[true,false,true,false,false]
<strong>解释：</strong>
&quot;FooBar&quot; 可以这样生成：&quot;Fo&quot; + &quot;o&quot; + &quot;Ba&quot; + &quot;r&quot;.
&quot;FootBall&quot; 可以这样生成：&quot;Fo&quot; + &quot;ot&quot; + &quot;Ba&quot; + &quot;ll&quot;.
"FooBar" 可以这样生成："Fo" + "o" + "Ba" + "r".
"FootBall" 可以这样生成："Fo" + "ot" + "Ba" + "ll".
</pre>
<p><strong>示例 3：</strong></p>
<pre><strong>输出：</strong>queries = [&quot;FooBar&quot;,&quot;FooBarTest&quot;,&quot;FootBall&quot;,&quot;FrameBuffer&quot;,&quot;ForceFeedBack&quot;], pattern = &quot;FoBaT&quot;
<strong>输入：</strong>[false,true,false,false,false]
<pre>
<strong>输入：</strong>queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FoBaT"
<strong>输出：</strong>[false,true,false,false,false]
<strong>解释： </strong>
&quot;FooBarTest&quot; 可以这样生成：&quot;Fo&quot; + &quot;o&quot; + &quot;Ba&quot; + &quot;r&quot; + &quot;T&quot; + &quot;est&quot;.
"FooBarTest" 可以这样生成："Fo" + "o" + "Ba" + "r" + "T" + "est".
</pre>
<p>&nbsp;</p>
<p><strong>提示：</strong></p>
<ol>
<li><code>1 &lt;= queries.length &lt;= 100</code></li>
<ul>
<li><code>1 &lt;= pattern.length, queries.length &lt;= 100</code></li>
<li><code>1 &lt;= queries[i].length &lt;= 100</code></li>
<li><code>1 &lt;= pattern.length &lt;= 100</code></li>
<li>所有字符串都仅由大写和小写英文字母组成。</li>
</ol>
<li><code>queries[i]</code> 和 <code>pattern</code> 由英文字母组成</li>
</ul>