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小墨
2023-12-09 18:42:21 +08:00
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leetcode-cn/problem (Chinese)/无限集中的最小数字 [smallest-number-in-infinite-set].html
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<ul>
<li><code>SmallestInfiniteSet()</code> 初始化 <strong>SmallestInfiniteSet</strong> 对象以包含 <strong>所有</strong> 正整数。</li>
<li><code>int popSmallest()</code> <strong>移除</strong> 并返回该无限集中的最小整数。</li>
<li><code>void addBack(int num)</code> 如果正整数 <code>num</code> <strong>不</strong> 存在于无限集中，则将一个 <code>num</code> <strong>添加</strong> 到该无限集中。</li>
<li><code>void addBack(int num)</code> 如果正整数 <code>num</code> <strong>不</strong> 存在于无限集中，则将一个 <code>num</code> <strong>添加</strong> 到该无限集最后。</li>
</ul>
<p>&nbsp;</p>
<p><strong>示例：</strong></p>
<pre><strong>输入</strong>
<pre>
<strong>输入</strong>
["SmallestInfiniteSet", "addBack", "popSmallest", "popSmallest", "popSmallest", "addBack", "popSmallest", "popSmallest", "popSmallest"]
[[], [2], [], [], [], [1], [], [], []]
<strong>输出</strong>