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小墨
2023-12-09 18:42:21 +08:00
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10
leetcode-cn/problem (Chinese)/字符串中的查找与替换 [find-and-replace-in-string].html
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@@ -24,20 +24,20 @@
<p><strong>示例 1：</strong></p>
<p><img src="https://assets.leetcode.com/uploads/2021/06/12/833-ex1.png" style="height: 251px; width: 411px;" /></p>
<p><img src="https://assets.leetcode.com/uploads/2021/06/12/833-ex1.png" /></p>
<pre>
<strong>输入：</strong>s = "abcd", indexes = [0,2], sources = ["a","cd"], targets = ["eee","ffff"]
<strong>输入：</strong>s = "abcd", indices = [0,2], sources = ["a","cd"], targets = ["eee","ffff"]
<strong>输出：</strong>"eeebffff"
<strong>解释：
</strong>"a" 从 s 中的索引 0 开始，所以它被替换为 "eee"。
"cd" 从 s 中的索引 2 开始，所以它被替换为 "ffff"。
</pre>
<p><strong>示例 2：</strong><img src="https://assets.leetcode.com/uploads/2021/06/12/833-ex2-1.png" style="height: 251px; width: 411px;" /></p>
<p><strong>示例 2：</strong><img src="https://assets.leetcode.com/uploads/2021/06/12/833-ex2-1.png" /></p>
<pre>
<strong>输入：</strong>s = "abcd", indexes = [0,2], sources = ["ab","ec"], targets = ["eee","ffff"]
<strong>输入：</strong>s = "abcd", indices = [0,2], sources = ["ab","ec"], targets = ["eee","ffff"]
<strong>输出：</strong>"eeecd"
<strong>解释：
</strong>"ab" 从 s 中的索引 0 开始，所以它被替换为 "eee"。
@@ -52,7 +52,7 @@
<li><code>1 &lt;= s.length &lt;= 1000</code></li>
<li><code>k == indices.length == sources.length == targets.length</code></li>
<li><code>1 &lt;= k &lt;= 100</code></li>
<li><code>0 &lt;= indexes[i] &lt; s.length</code></li>
<li><code>0 &lt;= indices[i] &lt; s.length</code></li>
<li><code>1 &lt;= sources[i].length, targets[i].length &lt;= 50</code></li>
<li><code>s</code> 仅由小写英文字母组成</li>
<li><code>sources[i]</code> 和 <code>targets[i]</code> 仅由小写英文字母组成</li>