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leetcode-cn/problem (Chinese)/反转每对括号间的子串 [reverse-substrings-between-each-pair-of-parentheses].html
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<p>给出一个字符串 <code>s</code>（仅含有小写英文字母和括号）。</p>
<p>给出一个字符串&nbsp;<code>s</code>（仅含有小写英文字母和括号）。</p>
<p>请你按照从括号内到外的顺序，逐层反转每对匹配括号中的字符串，并返回最终的结果。</p>
<p>注意，您的结果中 <strong>不应</strong> 包含任何括号。</p>
<p> </p>
<p>&nbsp;</p>
<p><strong>示例 1：</strong></p>
@@ -34,12 +34,12 @@
<strong>输出：</strong>"apmnolkjihgfedcbq"
</pre>
<p> </p>
<p>&nbsp;</p>
<p><strong>提示：</strong></p>
<ul>
<li><code>0 <= s.length <= 2000</code></li>
<li><code>1 &lt;= s.length &lt;= 2000</code></li>
<li><code>s</code> 中只有小写英文字母和括号</li>
<li>题目测试用例确保所有括号都是成对出现的</li>
</ul>