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小墨
2023-12-09 18:42:21 +08:00
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leetcode-cn/problem (Chinese)/二进制求和 [add-binary].html
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<p>给你两个二进制字符串，返回它们的和（用二进制表示）。</p>
<p>输入为 <strong>非空 </strong>字符串且只包含数字&nbsp;<code>1</code>&nbsp;和&nbsp;<code>0</code>。</p>
<p>给你两个二进制字符串 <code>a</code> 和 <code>b</code> ，以二进制字符串的形式返回它们的和。</p>
<p>&nbsp;</p>
<p><strong>示例&nbsp;1:</strong></p>
<p><strong>示例&nbsp;1：</strong></p>
<pre><strong>输入:</strong> a = &quot;11&quot;, b = &quot;1&quot;
<strong>输出:</strong> &quot;100&quot;</pre>
<pre>
<strong>输入:</strong>a = "11", b = "1"
<strong>输出：</strong>"100"</pre>
<p><strong>示例&nbsp;2:</strong></p>
<p><strong>示例&nbsp;2：</strong></p>
<pre><strong>输入:</strong> a = &quot;1010&quot;, b = &quot;1011&quot;
<strong>输出:</strong> &quot;10101&quot;</pre>
<pre>
<strong>输入：</strong>a = "1010", b = "1011"
<strong>输出：</strong>"10101"</pre>
<p>&nbsp;</p>
<p><strong>提示：</strong></p>
<ul>
<li>每个字符串仅由字符 <code>&#39;0&#39;</code> 或 <code>&#39;1&#39;</code> 组成。</li>
<li><code>1 &lt;= a.length, b.length &lt;= 10^4</code></li>
<li>字符串如果不是 <code>&quot;0&quot;</code> ，就都不含前导零。</li>
<li><code>1 &lt;= a.length, b.length &lt;= 10<sup>4</sup></code></li>
<li><code>a</code> 和 <code>b</code> 仅由字符 <code>'0'</code> 或 <code>'1'</code> 组成</li>
<li>字符串如果不是 <code>"0"</code> ，就不含前导零</li>
</ul>