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https://gitee.com/coder-xiaomo/leetcode-problemset
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存量题库数据更新
This commit is contained in:
@@ -7,17 +7,17 @@
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"boundTopicId": 2637,
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"title": "Tree Node",
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"titleSlug": "tree-node",
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"content": "<p>Table: <code>Tree</code></p>\n\n<pre>\n+-------------+------+\n| Column Name | Type |\n+-------------+------+\n| id | int |\n| p_id | int |\n+-------------+------+\nid is the primary key column for this table.\nEach row of this table contains information about the id of a node and the id of its parent node in a tree.\nThe given structure is always a valid tree.\n</pre>\n\n<p> </p>\n\n<p>Each node in the tree can be one of three types:</p>\n\n<ul>\n\t<li><strong>"Leaf"</strong>: if the node is a leaf node.</li>\n\t<li><strong>"Root"</strong>: if the node is the root of the tree.</li>\n\t<li><strong>"Inner"</strong>: If the node is neither a leaf node nor a root node.</li>\n</ul>\n\n<p>Write an SQL query to report the type of each node in the tree.</p>\n\n<p>Return the result table <strong>ordered</strong> by <code>id</code> <strong>in ascending order</strong>.</p>\n\n<p>The query result format is in the following example.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/10/22/tree1.jpg\" style=\"width: 304px; height: 224px;\" />\n<pre>\n<strong>Input:</strong> \nTree table:\n+----+------+\n| id | p_id |\n+----+------+\n| 1 | null |\n| 2 | 1 |\n| 3 | 1 |\n| 4 | 2 |\n| 5 | 2 |\n+----+------+\n<strong>Output:</strong> \n+----+-------+\n| id | type |\n+----+-------+\n| 1 | Root |\n| 2 | Inner |\n| 3 | Leaf |\n| 4 | Leaf |\n| 5 | Leaf |\n+----+-------+\n<strong>Explanation:</strong> \nNode 1 is the root node because its parent node is null and it has child nodes 2 and 3.\nNode 2 is an inner node because it has parent node 1 and child node 4 and 5.\nNodes 3, 4, and 5 are leaf nodes because they have parent nodes and they do not have child nodes.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/10/22/tree2.jpg\" style=\"width: 64px; height: 65px;\" />\n<pre>\n<strong>Input:</strong> \nTree table:\n+----+------+\n| id | p_id |\n+----+------+\n| 1 | null |\n+----+------+\n<strong>Output:</strong> \n+----+-------+\n| id | type |\n+----+-------+\n| 1 | Root |\n+----+-------+\n<strong>Explanation:</strong> If there is only one node on the tree, you only need to output its root attributes.\n</pre>\n",
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"content": "<p>Table: <code>Tree</code></p>\n\n<pre>\n+-------------+------+\n| Column Name | Type |\n+-------------+------+\n| id | int |\n| p_id | int |\n+-------------+------+\nid is the column with unique values for this table.\nEach row of this table contains information about the id of a node and the id of its parent node in a tree.\nThe given structure is always a valid tree.\n</pre>\n\n<p> </p>\n\n<p>Each node in the tree can be one of three types:</p>\n\n<ul>\n\t<li><strong>"Leaf"</strong>: if the node is a leaf node.</li>\n\t<li><strong>"Root"</strong>: if the node is the root of the tree.</li>\n\t<li><strong>"Inner"</strong>: If the node is neither a leaf node nor a root node.</li>\n</ul>\n\n<p>Write a solution to report the type of each node in the tree.</p>\n\n<p>Return the result table in <strong>any order</strong>.</p>\n\n<p>The result format is in the following example.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/10/22/tree1.jpg\" style=\"width: 304px; height: 224px;\" />\n<pre>\n<strong>Input:</strong> \nTree table:\n+----+------+\n| id | p_id |\n+----+------+\n| 1 | null |\n| 2 | 1 |\n| 3 | 1 |\n| 4 | 2 |\n| 5 | 2 |\n+----+------+\n<strong>Output:</strong> \n+----+-------+\n| id | type |\n+----+-------+\n| 1 | Root |\n| 2 | Inner |\n| 3 | Leaf |\n| 4 | Leaf |\n| 5 | Leaf |\n+----+-------+\n<strong>Explanation:</strong> \nNode 1 is the root node because its parent node is null and it has child nodes 2 and 3.\nNode 2 is an inner node because it has parent node 1 and child node 4 and 5.\nNodes 3, 4, and 5 are leaf nodes because they have parent nodes and they do not have child nodes.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/10/22/tree2.jpg\" style=\"width: 64px; height: 65px;\" />\n<pre>\n<strong>Input:</strong> \nTree table:\n+----+------+\n| id | p_id |\n+----+------+\n| 1 | null |\n+----+------+\n<strong>Output:</strong> \n+----+-------+\n| id | type |\n+----+-------+\n| 1 | Root |\n+----+-------+\n<strong>Explanation:</strong> If there is only one node on the tree, you only need to output its root attributes.\n</pre>\n",
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"translatedTitle": "树节点",
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"translatedContent": "<p>给定一个表 <code>tree</code>，<strong>id</strong> 是树节点的编号， <strong>p_id</strong> 是它父节点的 <strong>id 。</strong></p>\n\n<pre>+----+------+\n| id | p_id |\n+----+------+\n| 1 | null |\n| 2 | 1 |\n| 3 | 1 |\n| 4 | 2 |\n| 5 | 2 |\n+----+------+</pre>\n\n<p>树中每个节点属于以下三种类型之一：</p>\n\n<ul>\n\t<li>叶子：如果这个节点没有任何孩子节点。</li>\n\t<li>根：如果这个节点是整棵树的根，即没有父节点。</li>\n\t<li>内部节点：如果这个节点既不是叶子节点也不是根节点。</li>\n</ul>\n\n<p> </p>\n\n<p>写一个查询语句，输出所有节点的编号和节点的类型，并将结果按照节点编号排序。上面样例的结果为：</p>\n\n<p> </p>\n\n<pre>+----+------+\n| id | Type |\n+----+------+\n| 1 | Root |\n| 2 | Inner|\n| 3 | Leaf |\n| 4 | Leaf |\n| 5 | Leaf |\n+----+------+\n</pre>\n\n<p> </p>\n\n<p><strong>解释</strong></p>\n\n<ul>\n\t<li>节点 '1' 是根节点，因为它的父节点是 NULL ，同时它有孩子节点 '2' 和 '3' 。</li>\n\t<li>节点 '2' 是内部节点，因为它有父节点 '1' ，也有孩子节点 '4' 和 '5' 。</li>\n\t<li>节点 '3', '4' 和 '5' 都是叶子节点，因为它们都有父节点同时没有孩子节点。</li>\n\t<li>样例中树的形态如下：\n\t<p> </p>\n\n\t<pre>\t\t\t 1\n\t\t\t/ \\\n 2 3\n / \\\n 4 5\n</pre>\n\n\t<p> </p>\n\t</li>\n</ul>\n\n<p><strong>注意</strong></p>\n\n<p>如果树中只有一个节点，你只需要输出它的根属性。</p>\n",
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"translatedContent": "<p>表：<code>Tree</code></p>\n\n<pre>\n+-------------+------+\n| Column Name | Type |\n+-------------+------+\n| id | int |\n| p_id | int |\n+-------------+------+\nid 是该表中具有唯一值的列。\n该表的每行包含树中节点的 id 及其父节点的 id 信息。\n给定的结构总是一个有效的树。\n</pre>\n\n<p> </p>\n\n<p>树中的每个节点可以是以下三种类型之一：</p>\n\n<ul>\n\t<li><strong>\"Leaf\"</strong>：节点是叶子节点。</li>\n\t<li><strong>\"Root\"</strong>：节点是树的根节点。</li>\n\t<li><strong>\"lnner\"</strong>：节点既不是叶子节点也不是根节点。</li>\n</ul>\n\n<p>编写一个解决方案来报告树中每个节点的类型。</p>\n\n<p>以 <strong>任意顺序</strong> 返回结果表。</p>\n\n<p>结果格式如下所示。</p>\n\n<p> </p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/10/22/tree1.jpg\" style=\"width: 304px; height: 224px;\" />\n<pre>\n<b>输入：</b>\nTree table:\n+----+------+\n| id | p_id |\n+----+------+\n| 1 | null |\n| 2 | 1 |\n| 3 | 1 |\n| 4 | 2 |\n| 5 | 2 |\n+----+------+\n<b>输出：</b>\n+----+-------+\n| id | type |\n+----+-------+\n| 1 | Root |\n| 2 | Inner |\n| 3 | Leaf |\n| 4 | Leaf |\n| 5 | Leaf |\n+----+-------+\n<b>解释：</b>\n节点 1 是根节点，因为它的父节点为空，并且它有子节点 2 和 3。\n节点 2 是一个内部节点，因为它有父节点 1 和子节点 4 和 5。\n节点 3、4 和 5 是叶子节点，因为它们有父节点而没有子节点。\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/10/22/tree2.jpg\" style=\"width: 64px; height: 65px;\" />\n<pre>\n<b>输入：</b>\nTree table:\n+----+------+\n| id | p_id |\n+----+------+\n| 1 | null |\n+----+------+\n<b>输出：</b>\n+----+-------+\n| id | type |\n+----+-------+\n| 1 | Root |\n+----+-------+\n<b>解释：</b>如果树中只有一个节点，则只需要输出其根属性。\n</pre>\n",
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"isPaidOnly": false,
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"difficulty": "Medium",
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"likes": 66,
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"likes": 209,
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"dislikes": 0,
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"isLiked": null,
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"similarQuestions": "[]",
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"contributors": [],
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"topicTags": [
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{
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"name": "Database",
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@@ -45,16 +45,28 @@
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"langSlug": "oraclesql",
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"code": "/* Write your PL/SQL query statement below */",
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"__typename": "CodeSnippetNode"
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},
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{
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"lang": "Pandas",
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"langSlug": "pythondata",
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"code": "import pandas as pd\n\ndef tree_node(tree: pd.DataFrame) -> pd.DataFrame:\n ",
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"__typename": "CodeSnippetNode"
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},
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{
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"lang": "PostgreSQL",
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"langSlug": "postgresql",
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"code": "-- Write your PostgreSQL query statement below",
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"__typename": "CodeSnippetNode"
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}
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],
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"hints": [
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"You can judge the node type by querying whether the node's id shows up in p_id column and whether the node's p_id is null."
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],
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"solution": null,
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"status": null,
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"sampleTestCase": "{\"headers\": {\"Tree\": [\"id\", \"p_id\"]}, \"rows\": {\"Tree\": [[1,null],[2,1],[3,1],[4,2],[5,2]]}}",
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"metaData": "{\n \"mysql\": [\n \"Create table If Not Exists Tree (id int, p_id int)\"\n ],\n \"mssql\": [\n \"Create table Tree (id int, p_id int)\"\n ],\n \"oraclesql\": [\n \"Create table Tree (id int, p_id int)\"\n ],\n \"database\": true\n}",
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"sampleTestCase": "{\"headers\":{\"Tree\":[\"id\",\"p_id\"]},\"rows\":{\"Tree\":[[1,null],[2,1],[3,1],[4,2],[5,2]]}}",
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"metaData": "{\"mysql\":[\"Create table If Not Exists Tree (id int, p_id int)\"],\"mssql\":[\"Create table Tree (id int, p_id int)\"],\"oraclesql\":[\"Create table Tree (id int, p_id int)\"],\"database\":true,\"name\":\"tree_node\",\"pythondata\":[\"Tree = pd.DataFrame([], columns=['id', 'p_id']).astype({'id':'Int64', 'p_id':'Int64'})\"],\"postgresql\":[\"\\nCreate table If Not Exists Tree (id int, p_id int)\"],\"database_schema\":{\"Tree\":{\"id\":\"INT\",\"p_id\":\"INT\"}}}",
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"judgeType": "large",
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"mysqlSchemas": [
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@@ -67,7 +79,7 @@
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"insert into Tree (id, p_id) values ('5', '2')"
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],
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"enableRunCode": true,
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"envInfo": "{\"mysql\":[\"MySQL\",\"<p>\\u7248\\u672c\\uff1a<code>MySQL 8.0<\\/code><\\/p>\"],\"mssql\":[\"MS SQL Server\",\"<p>mssql server 2019.<\\/p>\"],\"oraclesql\":[\"Oracle\",\"<p>Oracle Sql 11.2.<\\/p>\"],\"pythondata\":[\"Pandas\",\"<p>Python 3.10 with Pandas 2.0.2 and NumPy 1.25.0<\\/p>\"],\"postgresql\":[\"PostgreSQL\",\"<p>PostgreSQL 16<\\/p>\"]}",
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@@ -75,7 +87,7 @@
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"editorType": "CKEDITOR",
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"style": "LEETCODE",
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"exampleTestcases": "{\"headers\": {\"Tree\": [\"id\", \"p_id\"]}, \"rows\": {\"Tree\": [[1,null],[2,1],[3,1],[4,2],[5,2]]}}\n{\"headers\": {\"Tree\": [\"id\", \"p_id\"]}, \"rows\": {\"Tree\": [[1,null]]}}",
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"exampleTestcases": "{\"headers\":{\"Tree\":[\"id\",\"p_id\"]},\"rows\":{\"Tree\":[[1,null],[2,1],[3,1],[4,2],[5,2]]}}\n{\"headers\":{\"Tree\":[\"id\",\"p_id\"]},\"rows\":{\"Tree\":[[1,null]]}}",
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"__typename": "QuestionNode"
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}
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}
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