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存量题库数据更新

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2023-12-09 18:42:21 +08:00
parent a788808cd7
commit c198538f10
10843 changed files with 288489 additions and 248355 deletions

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@@ -12,13 +12,44 @@
"translatedContent": "<p>给你一个下标从 <strong>0</strong>&nbsp;开始的整数数组&nbsp;<code>nums</code>&nbsp;。</p>\n\n<p><code>nums</code>&nbsp;一个长度为 <code>k</code>&nbsp;的 <strong>子序列</strong>&nbsp;指的是选出 <code>k</code>&nbsp;个 <strong>下标</strong>&nbsp;<code>i<sub>0</sub>&nbsp;&lt;&nbsp;i<sub>1</sub> &lt;&nbsp;... &lt; i<sub>k-1</sub></code>&nbsp;,如果这个子序列满足以下条件,我们说它是 <strong>平衡的</strong>&nbsp;</p>\n\n<ul>\n\t<li>对于范围&nbsp;<code>[1, k - 1]</code>&nbsp;内的所有&nbsp;<code>j</code>&nbsp;<code>nums[i<sub>j</sub>] - nums[i<sub>j-1</sub>] &gt;= i<sub>j</sub> - i<sub>j-1</sub></code>&nbsp;都成立。</li>\n</ul>\n\n<p><code>nums</code>&nbsp;长度为 <code>1</code>&nbsp;的 <strong>子序列</strong>&nbsp;是平衡的。</p>\n\n<p>请你返回一个整数,表示 <code>nums</code>&nbsp;<strong>平衡</strong>&nbsp;子序列里面的 <strong>最大元素和</strong>&nbsp;。</p>\n\n<p>一个数组的 <strong>子序列</strong>&nbsp;指的是从原数组中删除一些元素(<strong>也可能一个元素也不删除</strong>)后,剩余元素保持相对顺序得到的 <strong>非空</strong>&nbsp;新数组。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1</strong></p>\n\n<pre>\n<b>输入:</b>nums = [3,3,5,6]\n<b>输出:</b>14\n<b>解释:</b>这个例子中,选择子序列 [3,5,6] ,下标为 0 2 和 3 的元素被选中。\nnums[2] - nums[0] &gt;= 2 - 0 。\nnums[3] - nums[2] &gt;= 3 - 2 。\n所以这是一个平衡子序列且它的和是所有平衡子序列里最大的。\n包含下标 1 2 和 3 的子序列也是一个平衡的子序列。\n最大平衡子序列和为 14 。</pre>\n\n<p><strong class=\"example\">示例 2</strong></p>\n\n<pre>\n<b>输入:</b>nums = [5,-1,-3,8]\n<b>输出:</b>13\n<b>解释:</b>这个例子中,选择子序列 [5,8] ,下标为 0 和 3 的元素被选中。\nnums[3] - nums[0] &gt;= 3 - 0 。\n所以这是一个平衡子序列且它的和是所有平衡子序列里最大的。\n最大平衡子序列和为 13 。\n</pre>\n\n<p><strong class=\"example\">示例 3</strong></p>\n\n<pre>\n<b>输入:</b>nums = [-2,-1]\n<b>输出:</b>-1\n<b>解释:</b>这个例子中,选择子序列 [-1] 。\n这是一个平衡子序列而且它的和是 nums 所有平衡子序列里最大的。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>9</sup> &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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"Let <code>dp[x]</code> represent the maximum sum of a balanced subsequence ending at <code>x</code>.",
"Rewriting the formula <code>nums[i<sub>j</sub>] - nums[i<sub>j-1</sub>] >= i<sub>j</sub> - i<sub>j-1</sub></code> gives <code>nums[i<sub>j</sub>] - i<sub>j</sub> >= nums[i<sub>j-1</sub>] - i<sub>j-1</sub></code>.",