存量题库数据更新

leetcode/problem/sqrtx.html

@@ -1,23 +1,27 @@
-<p>Given a non-negative integer <code>x</code>,&nbsp;compute and return <em>the square root of</em> <code>x</code>.</p>
+<p>Given a non-negative integer <code>x</code>, return <em>the square root of </em><code>x</code><em> rounded down to the nearest integer</em>. The returned integer should be <strong>non-negative</strong> as well.</p>
 
-<p>Since the return type&nbsp;is an integer, the decimal digits are <strong>truncated</strong>, and only <strong>the integer part</strong> of the result&nbsp;is returned.</p>
+<p>You <strong>must not use</strong> any built-in exponent function or operator.</p>
 
-<p><strong>Note:&nbsp;</strong>You are not allowed to use any built-in exponent function or operator, such as <code>pow(x, 0.5)</code> or&nbsp;<code>x ** 0.5</code>.</p>
+<ul>
+	<li>For example, do not use <code>pow(x, 0.5)</code> in c++ or <code>x ** 0.5</code> in python.</li>
+</ul>
 
 <p>&nbsp;</p>
-<p><strong>Example 1:</strong></p>
+<p><strong class="example">Example 1:</strong></p>
 
 <pre>
 <strong>Input:</strong> x = 4
 <strong>Output:</strong> 2
+<strong>Explanation:</strong> The square root of 4 is 2, so we return 2.
 </pre>
 
-<p><strong>Example 2:</strong></p>
+<p><strong class="example">Example 2:</strong></p>
 
 <pre>
 <strong>Input:</strong> x = 8
 <strong>Output:</strong> 2
-<strong>Explanation:</strong> The square root of 8 is 2.82842..., and since the decimal part is truncated, 2 is returned.</pre>
+<strong>Explanation:</strong> The square root of 8 is 2.82842..., and since we round it down to the nearest integer, 2 is returned.
+</pre>
 
 <p>&nbsp;</p>
 <p><strong>Constraints:</strong></p>