mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-09-06 07:51:41 +08:00
存量题库数据更新
This commit is contained in:
@@ -3,7 +3,7 @@
|
||||
<p>Formally, we can partition the array if we can find indexes <code>i + 1 < j</code> with <code>(arr[0] + arr[1] + ... + arr[i] == arr[i + 1] + arr[i + 2] + ... + arr[j - 1] == arr[j] + arr[j + 1] + ... + arr[arr.length - 1])</code></p>
|
||||
|
||||
<p> </p>
|
||||
<p><strong>Example 1:</strong></p>
|
||||
<p><strong class="example">Example 1:</strong></p>
|
||||
|
||||
<pre>
|
||||
<strong>Input:</strong> arr = [0,2,1,-6,6,-7,9,1,2,0,1]
|
||||
@@ -11,14 +11,14 @@
|
||||
<strong>Explanation: </strong>0 + 2 + 1 = -6 + 6 - 7 + 9 + 1 = 2 + 0 + 1
|
||||
</pre>
|
||||
|
||||
<p><strong>Example 2:</strong></p>
|
||||
<p><strong class="example">Example 2:</strong></p>
|
||||
|
||||
<pre>
|
||||
<strong>Input:</strong> arr = [0,2,1,-6,6,7,9,-1,2,0,1]
|
||||
<strong>Output:</strong> false
|
||||
</pre>
|
||||
|
||||
<p><strong>Example 3:</strong></p>
|
||||
<p><strong class="example">Example 3:</strong></p>
|
||||
|
||||
<pre>
|
||||
<strong>Input:</strong> arr = [3,3,6,5,-2,2,5,1,-9,4]
|
||||
|
Reference in New Issue
Block a user