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存量题库数据更新
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@@ -5,7 +5,7 @@
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<p>Return <em>the <strong>maximum</strong> possible bitwise XOR of all elements of </em><code>nums</code><em> after applying the operation <strong>any number</strong> of times</em>.</p>
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<p> </p>
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<p><strong>Example 1:</strong></p>
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<p><strong class="example">Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> nums = [3,2,4,6]
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@@ -15,7 +15,7 @@ Now, nums = [3, 2, 4, 2] and the bitwise XOR of all the elements = 3 XOR 2 XOR 4
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It can be shown that 7 is the maximum possible bitwise XOR.
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Note that other operations may be used to achieve a bitwise XOR of 7.</pre>
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<p><strong>Example 2:</strong></p>
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<p><strong class="example">Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> nums = [1,2,3,9,2]
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