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存量题库数据更新

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2023-12-09 18:42:21 +08:00
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<p>You can assume that all dates occur in the <strong>same</strong> calendar year, which is <strong>not</strong> a leap year. Note that the number of days per month can be represented as: <code>[31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]</code>.</p>
<p>&nbsp;</p>
<p><strong>Example 1:</strong></p>
<p><strong class="example">Example 1:</strong></p>
<pre>
<strong>Input:</strong> arriveAlice = &quot;08-15&quot;, leaveAlice = &quot;08-18&quot;, arriveBob = &quot;08-16&quot;, leaveBob = &quot;08-19&quot;
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<strong>Explanation:</strong> Alice will be in Rome from August 15 to August 18. Bob will be in Rome from August 16 to August 19. They are both in Rome together on August 16th, 17th, and 18th, so the answer is 3.
</pre>
<p><strong>Example 2:</strong></p>
<p><strong class="example">Example 2:</strong></p>
<pre>
<strong>Input:</strong> arriveAlice = &quot;10-01&quot;, leaveAlice = &quot;10-31&quot;, arriveBob = &quot;11-01&quot;, leaveBob = &quot;12-31&quot;