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add leetcode problem-cn part5

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<p>给定一个字符串 <code>s</code> 和一个整数 <code>k</code>,从字符串开头算起,每计数至 <code>2k</code> 个字符,就反转这 <code>2k</code> 字符中的前 <code>k</code> 个字符。</p>
<ul>
<li>如果剩余字符少于 <code>k</code> 个,则将剩余字符全部反转。</li>
<li>如果剩余字符小于 <code>2k</code> 但大于或等于 <code>k</code> 个,则反转前 <code>k</code> 个字符,其余字符保持原样。</li>
</ul>
<p>&nbsp;</p>
<p><strong>示例 1</strong></p>
<pre>
<strong>输入:</strong>s = "abcdefg", k = 2
<strong>输出:</strong>"bacdfeg"
</pre>
<p><strong>示例 2</strong></p>
<pre>
<strong>输入:</strong>s = "abcd", k = 2
<strong>输出:</strong>"bacd"
</pre>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li><code>1 &lt;= s.length &lt;= 10<sup>4</sup></code></li>
<li><code>s</code> 仅由小写英文组成</li>
<li><code>1 &lt;= k &lt;= 10<sup>4</sup></code></li>
</ul>