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add leetcode problem-cn part5

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<p>给你一个二叉树的根结点&nbsp;<code>root</code>&nbsp;,请返回出现次数最多的子树元素和。如果有多个元素出现的次数相同,返回所有出现次数最多的子树元素和(不限顺序)。</p>
<p>一个结点的&nbsp;<strong>「子树元素和」</strong>&nbsp;定义为以该结点为根的二叉树上所有结点的元素之和(包括结点本身)。</p>
<p>&nbsp;</p>
<p><strong>示例 1</strong></p>
<p><img src="https://assets.leetcode.com/uploads/2021/04/24/freq1-tree.jpg" /></p>
<pre>
<strong>输入:</strong> root = [5,2,-3]
<strong>输出:</strong> [2,-3,4]
</pre>
<p><strong>示例&nbsp;2</strong></p>
<p><img src="https://assets.leetcode.com/uploads/2021/04/24/freq2-tree.jpg" /></p>
<pre>
<strong>输入:</strong> root = [5,2,-5]
<b>输出:</b> [2]
</pre>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li>节点数在&nbsp;<code>[1, 10<sup>4</sup>]</code>&nbsp;范围内</li>
<li><code>-10<sup>5</sup>&nbsp;&lt;= Node.val &lt;= 10<sup>5</sup></code></li>
</ul>