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add leetcode problem-cn part5
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<p>给你一个二叉树的根结点 <code>root</code> ,请返回出现次数最多的子树元素和。如果有多个元素出现的次数相同,返回所有出现次数最多的子树元素和(不限顺序)。</p>
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<p>一个结点的 <strong>「子树元素和」</strong> 定义为以该结点为根的二叉树上所有结点的元素之和(包括结点本身)。</p>
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<p> </p>
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<p><strong>示例 1:</strong></p>
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<p><img src="https://assets.leetcode.com/uploads/2021/04/24/freq1-tree.jpg" /></p>
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<pre>
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<strong>输入:</strong> root = [5,2,-3]
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<strong>输出:</strong> [2,-3,4]
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</pre>
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<p><strong>示例 2:</strong></p>
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<p><img src="https://assets.leetcode.com/uploads/2021/04/24/freq2-tree.jpg" /></p>
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<pre>
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<strong>输入:</strong> root = [5,2,-5]
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<b>输出:</b> [2]
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</pre>
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<p> </p>
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<p><strong>提示:</strong></p>
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<ul>
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<li>节点数在 <code>[1, 10<sup>4</sup>]</code> 范围内</li>
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<li><code>-10<sup>5</sup> <= Node.val <= 10<sup>5</sup></code></li>
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</ul>
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