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leetcode/problem/reverse-prefix-of-word.html
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<p>Given a <strong>0-indexed</strong> string <code>word</code> and a character <code>ch</code>, <strong>reverse</strong> the segment of <code>word</code> that starts at index <code>0</code> and ends at the index of the <strong>first occurrence</strong> of <code>ch</code> (<strong>inclusive</strong>). If the character <code>ch</code> does not exist in <code>word</code>, do nothing.</p>
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<ul>
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<li>For example, if <code>word = "abcdefd"</code> and <code>ch = "d"</code>, then you should <strong>reverse</strong> the segment that starts at <code>0</code> and ends at <code>3</code> (<strong>inclusive</strong>). The resulting string will be <code>"<u>dcba</u>efd"</code>.</li>
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</ul>
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<p>Return <em>the resulting string</em>.</p>
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<p> </p>
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<p><strong>Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> word = "<u>abcd</u>efd", ch = "d"
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<strong>Output:</strong> "<u>dcba</u>efd"
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<strong>Explanation:</strong> The first occurrence of "d" is at index 3.
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Reverse the part of word from 0 to 3 (inclusive), the resulting string is "dcbaefd".
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</pre>
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<p><strong>Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> word = "<u>xyxz</u>xe", ch = "z"
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<strong>Output:</strong> "<u>zxyx</u>xe"
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<strong>Explanation:</strong> The first and only occurrence of "z" is at index 3.
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Reverse the part of word from 0 to 3 (inclusive), the resulting string is "zxyxxe".
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</pre>
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<p><strong>Example 3:</strong></p>
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<pre>
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<strong>Input:</strong> word = "abcd", ch = "z"
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<strong>Output:</strong> "abcd"
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<strong>Explanation:</strong> "z" does not exist in word.
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You should not do any reverse operation, the resulting string is "abcd".
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</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>1 <= word.length <= 250</code></li>
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<li><code>word</code> consists of lowercase English letters.</li>
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<li><code>ch</code> is a lowercase English letter.</li>
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</ul>
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