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leetcode/problem/pairs-of-songs-with-total-durations-divisible-by-60.html

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+<p>You are given a list of songs where the <code>i<sup>th</sup></code> song has a duration of <code>time[i]</code> seconds.</p>
+
+<p>Return <em>the number of pairs of songs for which their total duration in seconds is divisible by</em> <code>60</code>. Formally, we want the number of indices <code>i</code>, <code>j</code> such that <code>i &lt; j</code> with <code>(time[i] + time[j]) % 60 == 0</code>.</p>
+
+<p>&nbsp;</p>
+<p><strong>Example 1:</strong></p>
+
+<pre>
+<strong>Input:</strong> time = [30,20,150,100,40]
+<strong>Output:</strong> 3
+<strong>Explanation:</strong> Three pairs have a total duration divisible by 60:
+(time[0] = 30, time[2] = 150): total duration 180
+(time[1] = 20, time[3] = 100): total duration 120
+(time[1] = 20, time[4] = 40): total duration 60
+</pre>
+
+<p><strong>Example 2:</strong></p>
+
+<pre>
+<strong>Input:</strong> time = [60,60,60]
+<strong>Output:</strong> 3
+<strong>Explanation:</strong> All three pairs have a total duration of 120, which is divisible by 60.
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>1 &lt;= time.length &lt;= 6 * 10<sup>4</sup></code></li>
+	<li><code>1 &lt;= time[i] &lt;= 500</code></li>
+</ul>