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leetcode/problem/minimum-operations-to-make-the-array-increasing.html

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+<p>You are given an integer array <code>nums</code> (<strong>0-indexed</strong>). In one operation, you can choose an element of the array and increment it by <code>1</code>.</p>
+
+
+
+<ul>
+
+	<li>For example, if <code>nums = [1,2,3]</code>, you can choose to increment <code>nums[1]</code> to make <code>nums = [1,<u><b>3</b></u>,3]</code>.</li>
+
+</ul>
+
+
+
+<p>Return <em>the <strong>minimum</strong> number of operations needed to make</em> <code>nums</code> <em><strong>strictly</strong> <strong>increasing</strong>.</em></p>
+
+
+
+<p>An array <code>nums</code> is <strong>strictly increasing</strong> if <code>nums[i] &lt; nums[i+1]</code> for all <code>0 &lt;= i &lt; nums.length - 1</code>. An array of length <code>1</code> is trivially strictly increasing.</p>
+
+
+
+<p>&nbsp;</p>
+
+<p><strong>Example 1:</strong></p>
+
+
+
+<pre>
+
+<strong>Input:</strong> nums = [1,1,1]
+
+<strong>Output:</strong> 3
+
+<strong>Explanation:</strong> You can do the following operations:
+
+1) Increment nums[2], so nums becomes [1,1,<u><strong>2</strong></u>].
+
+2) Increment nums[1], so nums becomes [1,<u><strong>2</strong></u>,2].
+
+3) Increment nums[2], so nums becomes [1,2,<u><strong>3</strong></u>].
+
+</pre>
+
+