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leetcode/problem/minimum-moves-to-reach-target-score.html

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+<p>You are playing a game with integers. You start with the integer <code>1</code> and you want to reach the integer <code>target</code>.</p>
+
+<p>In one move, you can either:</p>
+
+<ul>
+	<li><strong>Increment</strong> the current integer by one (i.e., <code>x = x + 1</code>).</li>
+	<li><strong>Double</strong> the current integer (i.e., <code>x = 2 * x</code>).</li>
+</ul>
+
+<p>You can use the <strong>increment</strong> operation <strong>any</strong> number of times, however, you can only use the <strong>double</strong> operation <strong>at most</strong> <code>maxDoubles</code> times.</p>
+
+<p>Given the two integers <code>target</code> and <code>maxDoubles</code>, return <em>the minimum number of moves needed to reach </em><code>target</code><em> starting with </em><code>1</code>.</p>
+
+<p>&nbsp;</p>
+<p><strong>Example 1:</strong></p>
+
+<pre>
+<strong>Input:</strong> target = 5, maxDoubles = 0
+<strong>Output:</strong> 4
+<strong>Explanation:</strong> Keep incrementing by 1 until you reach target.
+</pre>
+
+<p><strong>Example 2:</strong></p>
+
+<pre>
+<strong>Input:</strong> target = 19, maxDoubles = 2
+<strong>Output:</strong> 7
+<strong>Explanation:</strong> Initially, x = 1
+Increment 3 times so x = 4
+Double once so x = 8
+Increment once so x = 9
+Double again so x = 18
+Increment once so x = 19
+</pre>
+
+<p><strong>Example 3:</strong></p>
+
+<pre>
+<strong>Input:</strong> target = 10, maxDoubles = 4
+<strong>Output:</strong> 4
+<strong>Explanation:</strong><b> </b>Initially, x = 1
+Increment once so x = 2
+Double once so x = 4
+Increment once so x = 5
+Double again so x = 10
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>1 &lt;= target &lt;= 10<sup>9</sup></code></li>
+	<li><code>0 &lt;= maxDoubles &lt;= 100</code></li>
+</ul>