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算法题/count-operations-to-obtain-zero.html

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+<p>You are given two <strong>non-negative</strong> integers <code>num1</code> and <code>num2</code>.</p>
+
+<p>In one <strong>operation</strong>, if <code>num1 &gt;= num2</code>, you must subtract <code>num2</code> from <code>num1</code>, otherwise subtract <code>num1</code> from <code>num2</code>.</p>
+
+<ul>
+	<li>For example, if <code>num1 = 5</code> and <code>num2 = 4</code>, subtract <code>num2</code> from <code>num1</code>, thus obtaining <code>num1 = 1</code> and <code>num2 = 4</code>. However, if <code>num1 = 4</code> and <code>num2 = 5</code>, after one operation, <code>num1 = 4</code> and <code>num2 = 1</code>.</li>
+</ul>
+
+<p>Return <em>the <strong>number of operations</strong> required to make either</em> <code>num1 = 0</code> <em>or</em> <code>num2 = 0</code>.</p>
+
+<p>&nbsp;</p>
+<p><strong>Example 1:</strong></p>
+
+<pre>
+<strong>Input:</strong> num1 = 2, num2 = 3
+<strong>Output:</strong> 3
+<strong>Explanation:</strong> 
+- Operation 1: num1 = 2, num2 = 3. Since num1 &lt; num2, we subtract num1 from num2 and get num1 = 2, num2 = 3 - 2 = 1.
+- Operation 2: num1 = 2, num2 = 1. Since num1 &gt; num2, we subtract num2 from num1.
+- Operation 3: num1 = 1, num2 = 1. Since num1 == num2, we subtract num2 from num1.
+Now num1 = 0 and num2 = 1. Since num1 == 0, we do not need to perform any further operations.
+So the total number of operations required is 3.
+</pre>
+
+<p><strong>Example 2:</strong></p>
+
+<pre>
+<strong>Input:</strong> num1 = 10, num2 = 10
+<strong>Output:</strong> 1
+<strong>Explanation:</strong> 
+- Operation 1: num1 = 10, num2 = 10. Since num1 == num2, we subtract num2 from num1 and get num1 = 10 - 10 = 0.
+Now num1 = 0 and num2 = 10. Since num1 == 0, we are done.
+So the total number of operations required is 1.
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>0 &lt;= num1, num2 &lt;= 10<sup>5</sup></code></li>
+</ul>