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leetcode-cn/originData/single-number-iii.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>给定一个整数数组 <code>nums</code>，其中恰好有两个元素只出现一次，其余所有元素均出现两次。 找出只出现一次的那两个元素。你可以按 <strong>任意顺序</strong> 返回答案。</p>\n\n<p> </p>\n\n<p><strong>进阶：</strong>你的算法应该具有线性时间复杂度。你能否仅使用常数空间复杂度来实现？</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2,1,3,2,5]\n<strong>输出：</strong>[3,5]\n<strong>解释：</strong>[5, 3] 也是有效的答案。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [-1,0]\n<strong>输出：</strong>[-1,0]\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [0,1]\n<strong>输出：</strong>[1,0]\n</pre>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>2 <= nums.length <= 3 * 10<sup>4</sup></code></li>\n\t<li><code>-2<sup>31</sup> <= nums[i] <= 2<sup>31</sup> - 1</code></li>\n\t<li>除两个只出现一次的整数外，<code>nums</code> 中的其他数字都出现两次</li>\n</ul>\n",
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