update

leetcode-cn/originData/search-a-2d-matrix.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>编写一个高效的算法来判断 <code>m x n</code> 矩阵中，是否存在一个目标值。该矩阵具有如下特性：</p>\n\n<ul>\n\t<li>每行中的整数从左到右按升序排列。</li>\n\t<li>每行的第一个整数大于前一行的最后一个整数。</li>\n</ul>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/10/05/mat.jpg\" style=\"width: 322px; height: 242px;\" />\n<pre>\n<strong>输入：</strong>matrix = [[1,3,5,7],[10,11,16,20],[23,30,34,60]], target = 3\n<strong>输出：</strong>true\n</pre>\n\n<p><strong>示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/11/25/mat2.jpg\" style=\"width: 322px; height: 242px;\" />\n<pre>\n<strong>输入：</strong>matrix = [[1,3,5,7],[10,11,16,20],[23,30,34,60]], target = 13\n<strong>输出：</strong>false\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>m == matrix.length</code></li>\n\t<li><code>n == matrix[i].length</code></li>\n\t<li><code>1 <= m, n <= 100</code></li>\n\t<li><code>-10<sup>4</sup> <= matrix[i][j], target <= 10<sup>4</sup></code></li>\n</ul>\n",
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