coder-xiaomo/leetcode-problemset
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2022-03-29 16:56:27 +08:00
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leetcode-cn/originData/relative-sort-array.json
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@@ -12,7 +12,7 @@
"translatedContent": "<p>给你两个数组，<code>arr1</code> 和&nbsp;<code>arr2</code>，<code>arr2</code>&nbsp;中的元素各不相同，<code>arr2</code> 中的每个元素都出现在&nbsp;<code>arr1</code>&nbsp;中。</p>\n\n<p>对 <code>arr1</code>&nbsp;中的元素进行排序，使 <code>arr1</code> 中项的相对顺序和&nbsp;<code>arr2</code>&nbsp;中的相对顺序相同。未在&nbsp;<code>arr2</code>&nbsp;中出现过的元素需要按照升序放在&nbsp;<code>arr1</code>&nbsp;的末尾。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>arr1 = [2,3,1,3,2,4,6,7,9,2,19], arr2 = [2,1,4,3,9,6]\n<strong>输出：</strong>[2,2,2,1,4,3,3,9,6,7,19]\n</pre>\n\n<p><strong>示例 &nbsp;2:</strong></p>\n\n<pre>\n<strong>输入：</strong>arr1 = [28,6,22,8,44,17], arr2 = [22,28,8,6]\n<strong>输出：</strong>[22,28,8,6,17,44]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= arr1.length, arr2.length &lt;= 1000</code></li>\n\t<li><code>0 &lt;= arr1[i], arr2[i] &lt;= 1000</code></li>\n\t<li><code>arr2</code>&nbsp;中的元素&nbsp;<code>arr2[i]</code>&nbsp;&nbsp;<strong>各不相同</strong>&nbsp;</li>\n\t<li><code>arr2</code> 中的每个元素&nbsp;<code>arr2[i]</code>&nbsp;都出现在&nbsp;<code>arr1</code>&nbsp;中</li>\n</ul>\n",
"isPaidOnly": false,
"difficulty": "Easy",
"likes": 206,
"likes": 207,
"dislikes": 0,
"isLiked": null,
"similarQuestions": "[]",
@@ -155,7 +155,7 @@
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"hints": [
"Using a hashmap, we can map the values of arr2 to their position in arr2.",
"After, we can use a custom sorting function."