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leetcode-cn/originData/power-of-two.json
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@@ -12,7 +12,7 @@
"translatedContent": "<p>给你一个整数 <code>n</code>，请你判断该整数是否是 2 的幂次方。如果是，返回 <code>true</code> ；否则，返回 <code>false</code> 。</p>\n\n<p>如果存在一个整数 <code>x</code> 使得 <code>n == 2<sup>x</sup></code> ，则认为 <code>n</code> 是 2 的幂次方。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 1\n<strong>输出：</strong>true\n<strong>解释：</strong>2<sup>0</sup> = 1\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 16\n<strong>输出：</strong>true\n<strong>解释：</strong>2<sup>4</sup> = 16\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 3\n<strong>输出：</strong>false\n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 4\n<strong>输出：</strong>true\n</pre>\n\n<p><strong>示例 5：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 5\n<strong>输出：</strong>false\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>-2<sup>31</sup> <= n <= 2<sup>31</sup> - 1</code></li>\n</ul>\n\n<p> </p>\n\n<p><strong>进阶：</strong>你能够不使用循环/递归解决此问题吗？</p>\n",
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"difficulty": "Easy",
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"similarQuestions": "[{\"title\": \"Number of 1 Bits\", \"titleSlug\": \"number-of-1-bits\", \"difficulty\": \"Easy\", \"translatedTitle\": \"\\u4f4d1\\u7684\\u4e2a\\u6570\"}, {\"title\": \"Power of Three\", \"titleSlug\": \"power-of-three\", \"difficulty\": \"Easy\", \"translatedTitle\": \"3 \\u7684\\u5e42\"}, {\"title\": \"Power of Four\", \"titleSlug\": \"power-of-four\", \"difficulty\": \"Easy\", \"translatedTitle\": \"4\\u7684\\u5e42\"}]",
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