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leetcode-cn/originData/non-overlapping-intervals.json
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@@ -12,7 +12,7 @@
"translatedContent": "<p>给定一个区间的集合&nbsp;<code>intervals</code>&nbsp;，其中 <code>intervals[i] = [start<sub>i</sub>, end<sub>i</sub>]</code>&nbsp;。返回 <em>需要移除区间的最小数量，使剩余区间互不重叠&nbsp;</em>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong> intervals = [[1,2],[2,3],[3,4],[1,3]]\n<strong>输出:</strong> 1\n<strong>解释:</strong> 移除 [1,3] 后，剩下的区间没有重叠。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong> intervals = [ [1,2], [1,2], [1,2] ]\n<strong>输出:</strong> 2\n<strong>解释:</strong> 你需要移除两个 [1,2] 来使剩下的区间没有重叠。\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre>\n<strong>输入:</strong> intervals = [ [1,2], [2,3] ]\n<strong>输出:</strong> 0\n<strong>解释:</strong> 你不需要移除任何区间，因为它们已经是无重叠的了。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= intervals.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>intervals[i].length == 2</code></li>\n\t<li><code>-5 * 10<sup>4</sup>&nbsp;&lt;= start<sub>i</sub>&nbsp;&lt; end<sub>i</sub>&nbsp;&lt;= 5 * 10<sup>4</sup></code></li>\n</ul>\n",
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"difficulty": "Medium",
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"similarQuestions": "[{\"title\": \"Minimum Number of Arrows to Burst Balloons\", \"titleSlug\": \"minimum-number-of-arrows-to-burst-balloons\", \"difficulty\": \"Medium\", \"translatedTitle\": \"\\u7528\\u6700\\u5c11\\u6570\\u91cf\\u7684\\u7bad\\u5f15\\u7206\\u6c14\\u7403\"}]",
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