update

leetcode-cn/originData/interleaving-string.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>给定三个字符串&nbsp;<code>s1</code>、<code>s2</code>、<code>s3</code>，请你帮忙验证&nbsp;<code>s3</code>&nbsp;是否是由&nbsp;<code>s1</code>&nbsp;和&nbsp;<code>s2</code><em> </em><strong>交错 </strong>组成的。</p>\n\n<p>两个字符串 <code>s</code> 和 <code>t</code> <strong>交错</strong> 的定义与过程如下，其中每个字符串都会被分割成若干 <strong>非空</strong> 子字符串：</p>\n\n<ul>\n\t<li><code>s = s<sub>1</sub> + s<sub>2</sub> + ... + s<sub>n</sub></code></li>\n\t<li><code>t = t<sub>1</sub> + t<sub>2</sub> + ... + t<sub>m</sub></code></li>\n\t<li><code>|n - m| &lt;= 1</code></li>\n\t<li><strong>交错</strong> 是 <code>s<sub>1</sub> + t<sub>1</sub> + s<sub>2</sub> + t<sub>2</sub> + s<sub>3</sub> + t<sub>3</sub> + ...</code> 或者 <code>t<sub>1</sub> + s<sub>1</sub> + t<sub>2</sub> + s<sub>2</sub> + t<sub>3</sub> + s<sub>3</sub> + ...</code></li>\n</ul>\n\n<p><strong>注意：</strong><code>a + b</code> 意味着字符串 <code>a</code> 和 <code>b</code> 连接。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/09/02/interleave.jpg\" />\n<pre>\n<strong>输入：</strong>s1 = \"aabcc\", s2 = \"dbbca\", s3 = \"aadbbcbcac\"\n<strong>输出：</strong>true\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s1 = \"aabcc\", s2 = \"dbbca\", s3 = \"aadbbbaccc\"\n<strong>输出：</strong>false\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>s1 = \"\", s2 = \"\", s3 = \"\"\n<strong>输出：</strong>true\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= s1.length, s2.length &lt;= 100</code></li>\n\t<li><code>0 &lt;= s3.length &lt;= 200</code></li>\n\t<li><code>s1</code>、<code>s2</code>、和 <code>s3</code> 都由小写英文字母组成</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>进阶：</strong>您能否仅使用 <code>O(s2.length)</code> 额外的内存空间来解决它?</p>\n",
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