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"translatedContent": "<p>你是一个专业的小偷,计划偷窃沿街的房屋,每间房内都藏有一定的现金。这个地方所有的房屋都 <strong>围成一圈</strong> ,这意味着第一个房屋和最后一个房屋是紧挨着的。同时,相邻的房屋装有相互连通的防盗系统,<strong>如果两间相邻的房屋在同一晚上被小偷闯入,系统会自动报警</strong> 。</p>\n\n<p>给定一个代表每个房屋存放金额的非负整数数组,计算你 <strong>在不触动警报装置的情况下</strong> ,今晚能够偷窃到的最高金额。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [2,3,2]\n<strong>输出:</strong>3\n<strong>解释:</strong>你不能先偷窃 1 号房屋(金额 = 2),然后偷窃 3 号房屋(金额 = 2), 因为他们是相邻的。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [1,2,3,1]\n<strong>输出:</strong>4\n<strong>解释:</strong>你可以先偷窃 1 号房屋(金额 = 1),然后偷窃 3 号房屋(金额 = 3)。\n 偷窃到的最高金额 = 1 + 3 = 4 。</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [1,2,3]\n<strong>输出:</strong>3\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 100</code></li>\n\t<li><code>0 <= nums[i] <= 1000</code></li>\n</ul>\n",
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"Since House[1] and House[n] are adjacent, they cannot be robbed together. Therefore, the problem becomes to rob either House[1]-House[n-1] or House[2]-House[n], depending on which choice offers more money. Now the problem has degenerated to the <a href =\"https://leetcode.com/problems/house-robber/description/\">House Robber</a>, which is already been solved."
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