update

leetcode-cn/originData/greatest-sum-divisible-by-three.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>给你一个整数数组&nbsp;<code>nums</code>，请你找出并返回能被三整除的元素最大和。</p>\n\n<ol>\n</ol>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>nums = [3,6,5,1,8]\n<strong>输出：</strong>18\n<strong>解释：</strong>选出数字 3, 6, 1 和 8，它们的和是 18（可被 3 整除的最大和）。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>nums = [4]\n<strong>输出：</strong>0\n<strong>解释：</strong>4 不能被 3 整除，所以无法选出数字，返回 0。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>nums = [1,2,3,4,4]\n<strong>输出：</strong>12\n<strong>解释：</strong>选出数字 1, 3, 4 以及 4，它们的和是 12（可被 3 整除的最大和）。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 4 * 10^4</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10^4</code></li>\n</ul>\n",
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             "difficulty": "Medium",
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             "hints": [
                 "Represent the state as DP[pos][mod]: maximum possible sum starting in the position \"pos\" in the array where the current sum modulo 3 is equal to mod."
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