update

leetcode-cn/originData/find-the-distance-value-between-two-arrays.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>给你两个整数数组&nbsp;<code>arr1</code>&nbsp;，&nbsp;<code>arr2</code>&nbsp;和一个整数&nbsp;<code>d</code>&nbsp;，请你返回两个数组之间的&nbsp;<strong>距离值</strong>&nbsp;。</p>\n\n<p>「<strong>距离值</strong>」<strong>&nbsp;</strong>定义为符合此距离要求的元素数目：对于元素&nbsp;<code>arr1[i]</code>&nbsp;，不存在任何元素&nbsp;<code>arr2[j]</code>&nbsp;满足 <code>|arr1[i]-arr2[j]| &lt;= d</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>arr1 = [4,5,8], arr2 = [10,9,1,8], d = 2\n<strong>输出：</strong>2\n<strong>解释：</strong>\n对于 arr1[0]=4 我们有：\n|4-10|=6 &gt; d=2 \n|4-9|=5 &gt; d=2 \n|4-1|=3 &gt; d=2 \n|4-8|=4 &gt; d=2 \n所以 arr1[0]=4 符合距离要求\n\n对于 arr1[1]=5 我们有：\n|5-10|=5 &gt; d=2 \n|5-9|=4 &gt; d=2 \n|5-1|=4 &gt; d=2 \n|5-8|=3 &gt; d=2\n所以 arr1[1]=5 也符合距离要求\n\n对于 arr1[2]=8 我们有：\n<strong>|8-10|=2 &lt;= d=2</strong>\n<strong>|8-9|=1 &lt;= d=2</strong>\n|8-1|=7 &gt; d=2\n<strong>|8-8|=0 &lt;= d=2</strong>\n存在距离小于等于 2 的情况，不符合距离要求 \n\n故而只有 arr1[0]=4 和 arr1[1]=5 两个符合距离要求，距离值为 2</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>arr1 = [1,4,2,3], arr2 = [-4,-3,6,10,20,30], d = 3\n<strong>输出：</strong>2\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>arr1 = [2,1,100,3], arr2 = [-5,-2,10,-3,7], d = 6\n<strong>输出：</strong>1\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= arr1.length, arr2.length &lt;= 500</code></li>\n\t<li><code>-10^3 &lt;= arr1[i], arr2[j] &lt;= 10^3</code></li>\n\t<li><code>0 &lt;= d &lt;= 100</code></li>\n</ul>\n",
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             "hints": [
                 "Sort 'arr2' and use binary search to get the closest element for each 'arr1[i]', it gives a time complexity of O(nlogn)."
             ],