update

leetcode-cn/originData/find-original-array-from-doubled-array.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>一个整数数组&nbsp;<code>original</code>&nbsp;可以转变成一个 <strong>双倍</strong>&nbsp;数组&nbsp;<code>changed</code>&nbsp;，转变方式为将 <code>original</code>&nbsp;中每个元素 <strong>值乘以 2 </strong>加入数组中，然后将所有元素 <strong>随机打乱</strong>&nbsp;。</p>\n\n<p>给你一个数组&nbsp;<code>changed</code>&nbsp;，如果&nbsp;<code>change</code>&nbsp;是&nbsp;<strong>双倍</strong>&nbsp;数组，那么请你返回&nbsp;<code>original</code>数组，否则请返回空数组。<code>original</code>&nbsp;的元素可以以&nbsp;<strong>任意</strong>&nbsp;顺序返回。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>changed = [1,3,4,2,6,8]\n<b>输出：</b>[1,3,4]\n<b>解释：</b>一个可能的 original 数组为 [1,3,4] :\n- 将 1 乘以 2 ，得到 1 * 2 = 2 。\n- 将 3 乘以 2 ，得到 3 * 2 = 6 。\n- 将 4 乘以 2 ，得到 4 * 2 = 8 。\n其他可能的原数组方案为 [4,3,1] 或者 [3,1,4] 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>changed = [6,3,0,1]\n<b>输出：</b>[]\n<b>解释：</b>changed 不是一个双倍数组。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><b>输入：</b>changed = [1]\n<b>输出：</b>[]\n<b>解释：</b>changed 不是一个双倍数组。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= changed.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= changed[i] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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             "hints": [
                 "If changed is a doubled array, you should be able to delete elements and their doubled values until the array is empty.",
                 "Which element is guaranteed to not be a doubled value? It is the smallest element.",