update

leetcode-cn/originData/determine-whether-matrix-can-be-obtained-by-rotation.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>给你两个大小为 <code>n x n</code> 的二进制矩阵 <code>mat</code> 和 <code>target</code> 。现<strong> 以 90 度顺时针轮转 </strong>矩阵 <code>mat</code> 中的元素 <strong>若干次</strong> ，如果能够使 <code>mat</code> 与 <code>target</code> 一致，返回 <code>true</code> ；否则，返回<em> </em><code>false</code><em> 。</em></p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/05/20/grid3.png\" style=\"width: 301px; height: 121px;\" />\n<pre>\n<strong>输入：</strong>mat = [[0,1],[1,0]], target = [[1,0],[0,1]]\n<strong>输出：</strong>true\n<strong>解释：</strong>顺时针轮转 90 度一次可以使 mat 和 target 一致。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/05/20/grid4.png\" style=\"width: 301px; height: 121px;\" />\n<pre>\n<strong>输入：</strong>mat = [[0,1],[1,1]], target = [[1,0],[0,1]]\n<strong>输出：</strong>false\n<strong>解释：</strong>无法通过轮转矩阵中的元素使 equal 与 target 一致。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/05/26/grid4.png\" style=\"width: 661px; height: 184px;\" />\n<pre>\n<strong>输入：</strong>mat = [[0,0,0],[0,1,0],[1,1,1]], target = [[1,1,1],[0,1,0],[0,0,0]]\n<strong>输出：</strong>true\n<strong>解释：</strong>顺时针轮转 90 度两次可以使 mat 和 target 一致。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == mat.length == target.length</code></li>\n\t<li><code>n == mat[i].length == target[i].length</code></li>\n\t<li><code>1 <= n <= 10</code></li>\n\t<li><code>mat[i][j]</code> 和 <code>target[i][j]</code> 不是 <code>0</code> 就是 <code>1</code></li>\n</ul>\n",
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             "hints": [
                 "What is the maximum number of rotations you have to check?",
                 "Is there a formula you can use to rotate a matrix 90 degrees?"