update

leetcode-cn/originData/customer-placing-the-largest-number-of-orders.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>表:&nbsp;<code>Orders</code></p>\n\n<pre>\n+-----------------+----------+\n| Column Name     | Type     |\n+-----------------+----------+\n| order_number    | int      |\n| customer_number | int      |\n+-----------------+----------+\nOrder_number是该表的主键。\n此表包含关于订单ID和客户ID的信息。\n</pre>\n\n<p>&nbsp;</p>\n\n<p>编写一个SQL查询，为下了 <strong>最多订单</strong> 的客户查找 <code>customer_number</code> 。</p>\n\n<p>测试用例生成后， <strong>恰好有一个客户</strong> 比任何其他客户下了更多的订单。</p>\n\n<p>查询结果格式如下所示。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong> \nOrders 表:\n+--------------+-----------------+\n| order_number | customer_number |\n+--------------+-----------------+\n| 1            | 1               |\n| 2            | 2               |\n| 3            | 3               |\n| 4            | 3               |\n+--------------+-----------------+\n<strong>输出:</strong> \n+-----------------+\n| customer_number |\n+-----------------+\n| 3               |\n+-----------------+\n<strong>解释:</strong> \ncustomer_number 为 '3' 的顾客有两个订单，比顾客 '1' 或者 '2' 都要多，因为他们只有一个订单。\n所以结果是该顾客的 customer_number ，也就是 3 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>进阶：</strong> 如果有多位顾客订单数并列最多，你能找到他们所有的 <code>customer_number</code> 吗？</p>\n",
             "isPaidOnly": false,
             "difficulty": "Easy",
-            "likes": 28,
+            "likes": 29,
             "dislikes": 0,
             "isLiked": null,
             "similarQuestions": "[]",
@@ -47,7 +47,7 @@
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             "hints": [
                 "MySQL uses a different expression to get the first records other than MSSQL's TOP expression."
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