update

leetcode-cn/originData/can-make-arithmetic-progression-from-sequence.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>给你一个数字数组 <code>arr</code> 。</p>\n\n<p>如果一个数列中，任意相邻两项的差总等于同一个常数，那么这个数列就称为 <strong>等差数列</strong> 。</p>\n\n<p>如果可以重新排列数组形成等差数列，请返回 <code>true</code> ；否则，返回 <code>false</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>arr = [3,5,1]\n<strong>输出：</strong>true\n<strong>解释：</strong>对数组重新排序得到 [1,3,5] 或者 [5,3,1] ，任意相邻两项的差分别为 2 或 -2 ，可以形成等差数列。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>arr = [1,2,4]\n<strong>输出：</strong>false\n<strong>解释：</strong>无法通过重新排序得到等差数列。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= arr.length &lt;= 1000</code></li>\n\t<li><code>-10^6 &lt;= arr[i] &lt;= 10^6</code></li>\n</ul>\n",
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             "difficulty": "Easy",
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@@ -143,7 +143,7 @@
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             "hints": [
                 "Consider that any valid arithmetic progression will be in sorted order.",
                 "Sort the array, then check if the differences of all consecutive elements are equal."