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小墨
2022-03-29 16:56:27 +08:00
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leetcode-cn/originData/broken-calculator.json
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@@ -12,7 +12,7 @@
"translatedContent": "<p>在显示着数字&nbsp;<code>startValue</code>&nbsp;的坏计算器上，我们可以执行以下两种操作：</p>\n\n<ul>\n\t<li><strong>双倍（Double）：</strong>将显示屏上的数字乘 2；</li>\n\t<li><strong>递减（Decrement）：</strong>将显示屏上的数字减 <code>1</code> 。</li>\n</ul>\n\n<p>给定两个整数&nbsp;<code>startValue</code>&nbsp;和&nbsp;<code>target</code>&nbsp;。返回显示数字&nbsp;<code>target</code>&nbsp;所需的最小操作数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>startValue = 2, target = 3\n<strong>输出：</strong>2\n<strong>解释：</strong>先进行双倍运算，然后再进行递减运算 {2 -&gt; 4 -&gt; 3}.\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>startValue = 5, target = 8\n<strong>输出：</strong>2\n<strong>解释：</strong>先递减，再双倍 {5 -&gt; 4 -&gt; 8}.\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>startValue = 3, target = 10\n<strong>输出：</strong>3\n<strong>解释：</strong>先双倍，然后递减，再双倍 {3 -&gt; 6 -&gt; 5 -&gt; 10}.\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= x, y &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
"isPaidOnly": false,
"difficulty": "Medium",
"likes": 138,
"likes": 139,
"dislikes": 0,
"isLiked": null,
"similarQuestions": "[{\"title\": \"2 Keys Keyboard\", \"titleSlug\": \"2-keys-keyboard\", \"difficulty\": \"Medium\", \"translatedTitle\": \"\\u53ea\\u6709\\u4e24\\u4e2a\\u952e\\u7684\\u952e\\u76d8\"}]",
@@ -143,7 +143,7 @@
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"hints": [],
"solution": {
"id": "141",