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leetcode-cn/originData/best-time-to-buy-and-sell-stock.json
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@@ -12,7 +12,7 @@
"translatedContent": "<p>给定一个数组 <code>prices</code> ，它的第 <code>i</code> 个元素 <code>prices[i]</code> 表示一支给定股票第 <code>i</code> 天的价格。</p>\n\n<p>你只能选择 <strong>某一天</strong> 买入这只股票，并选择在 <strong>未来的某一个不同的日子</strong> 卖出该股票。设计一个算法来计算你所能获取的最大利润。</p>\n\n<p>返回你可以从这笔交易中获取的最大利润。如果你不能获取任何利润，返回 <code>0</code> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>[7,1,5,3,6,4]\n<strong>输出：</strong>5\n<strong>解释：</strong>在第 2 天（股票价格 = 1）的时候买入，在第 5 天（股票价格 = 6）的时候卖出，最大利润 = 6-1 = 5 。\n 注意利润不能是 7-1 = 6, 因为卖出价格需要大于买入价格；同时，你不能在买入前卖出股票。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>prices = [7,6,4,3,1]\n<strong>输出：</strong>0\n<strong>解释：</strong>在这种情况下, 没有交易完成, 所以最大利润为 0。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= prices.length <= 10<sup>5</sup></code></li>\n\t<li><code>0 <= prices[i] <= 10<sup>4</sup></code></li>\n</ul>\n",
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