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leetcode-cn/problem (Chinese)/跳过交替单元格的之字形遍历 [zigzag-grid-traversal-with-skip].html Normal file
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<p>给你一个 <code>m x n</code> 的二维数组 <code>grid</code>，数组由&nbsp;<strong>正整数</strong> 组成。</p>
<p>你的任务是以&nbsp;<strong>之字形&nbsp;</strong>遍历 <code>grid</code>，同时跳过每个&nbsp;<strong>交替&nbsp;</strong>的单元格。</p>
<p>之字形遍历的定义如下：</p>
<ul>
<li>从左上角的单元格 <code>(0, 0)</code> 开始。</li>
<li>在当前行中向 <strong>右</strong> 移动，直到到达该行的末尾。</li>
<li>下移到下一行，然后在该行中向&nbsp;<strong>左</strong><em>&nbsp;</em>移动，直到到达该行的开头。</li>
<li>继续在行间交替向右和向左移动，直到所有行都被遍历完。</li>
</ul>
<p><strong>注意：</strong>在遍历过程中，必须跳过每个&nbsp;<strong>交替&nbsp;</strong>的单元格。</p>
<p>返回一个整数数组 <code>result</code>，其中包含按&nbsp;<strong>顺序&nbsp;</strong>记录的、且跳过交替单元格后的之字形遍历中访问到的单元格值。</p>
<p>&nbsp;</p>
<p><strong class="example">示例 1：</strong></p>
<div class="example-block">
<p><strong>输入：</strong> <span class="example-io">grid = [[1,2],[3,4]]</span></p>
<p><strong>输出：</strong> <span class="example-io">[1,4]</span></p>
<p><strong>解释：</strong></p>
<p><strong><img alt="" src="https://assets.leetcode.com/uploads/2024/11/23/4012_example0.png" style="width: 200px; height: 200px;" /></strong></p>
</div>
<p><strong class="example">示例 2：</strong></p>
<div class="example-block">
<p><strong>输入：</strong> <span class="example-io">grid = [[2,1],[2,1],[2,1]]</span></p>
<p><strong>输出：</strong> <span class="example-io">[2,1,2]</span></p>
<p><strong>解释：</strong></p>
<p><img alt="" src="https://assets.leetcode.com/uploads/2024/11/23/4012_example1.png" style="width: 200px; height: 240px;" /></p>
</div>
<p><strong class="example">示例 3：</strong></p>
<div class="example-block">
<p><strong>输入：</strong> <span class="example-io">grid = [[1,2,3],[4,5,6],[7,8,9]]</span></p>
<p><strong>输出：</strong> <span class="example-io">[1,3,5,7,9]</span></p>
<p><strong>解释：</strong></p>
<p><img alt="" src="https://assets.leetcode.com/uploads/2024/11/23/4012_example2.png" style="width: 260px; height: 250px;" /></p>
</div>
<p>&nbsp;</p>
<p><strong>提示：</strong></p>
<ul>
<li><code>2 &lt;= n == grid.length &lt;= 50</code></li>
<li><code>2 &lt;= m == grid[i].length &lt;= 50</code></li>
<li><code>1 &lt;= grid[i][j] &lt;= 2500</code></li>
</ul>